S5 Biology: Genetics and Mendelian Inheritance (Paper 4 (error clinic))
- 2026-11-14
S5 Biology: Genetics and Mendelian Inheritance (Paper 4 (error clinic))
This paper corrects ten common errors in Mendelian genetics one by one, covering inverted ratios, heterozygote phenotype, the lost recessive allele, blood-group combinations, the direction of X-linked transmission and the partner used in a test cross.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S5 Biology: Genetics and Mendelian Inheritance |
| Level | S3 |
02 Questions (10 items)
- FoundationError clinic: the F2 ratio 3 : 1 was written as three short to one tall. What should it be?
- FoundationError clinic: Tt was described as short. What is the correct phenotype?
- FoundationError clinic: the recessive allele was said to vanish in F1. What is correct?
- IntermediateError clinic: parents IA i and IB i were said to be unable to have a type O child. What is the probability?
- IntermediateError clinic: a colour-blind father was said to pass the allele to his sons. What is correct?
- IntermediateError clinic: a test cross was said to use a homozygous dominant partner. What is correct?
- ChallengeError clinic: from Rr x Rr, 400 of 800 seeds were said to be wrinkled. What is correct?
- ChallengeError clinic: AB and O parents were said to be able to have an AB child. What is the probability?
- ChallengeError clinic: two tall plants were assumed to share one genotype. What is correct?
- Error redoError clinic: Tt x tt was said to give a 3 : 1 ratio. What ratio and count are correct?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | Three tall to one short. | The dominant class is the larger one in F2. |
| 2 | Tt is tall. | T is dominant, so one dominant allele is enough. |
| 3 | The recessive allele remains present but is not expressed. | A heterozygote carries the recessive allele, which reappears in F2. |
| 4 | They can, with probability one quarter, that is 25 percent. | Each parent can pass i, and ii appears once in four combinations. |
| 5 | No, a father gives sons only Y; the X-linked allele goes to his daughters. | Sons receive X from the mother, so a carrier mother is needed for a colour-blind son. |
| 6 | Use a homozygous recessive partner such as tt. | The recessive parent masks nothing, so offspring phenotypes reveal the unknown gametes. |
| 7 | 200 seeds. | Wrinkled seeds take one quarter, and 800 divided by 4 is 200. |
| 8 | Zero percent, a type AB child is impossible. | The O parent carries only i, so no child can receive a second codominant allele. |
| 9 | Not necessarily, they may be TT or Tt. | A heterozygote and a dominant homozygote look the same, so a test cross is needed. |
| 10 | 1 : 1, so about 50 of 100 plants are short. | A heterozygote crossed with a recessive homozygote gives two genotype classes in equal numbers. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
Sort reproduction questions by place and order first: the testes make sperm, the ovaries make eggs, fertilisation happens in the oviduct and implantation in the uterus, while the placenta and umbilical cord carry nutrients and oxygen; for cycle questions draw the days on one timeline and remember the fertile window runs about three days before and one day after ovulation.Tutor Registration →
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