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S5 Biology: Genetics and Mendelian Inheritance (Paper 4 (error clinic))

S5 Biology: Genetics and Mendelian Inheritance (Paper 4 (error clinic))

  • 2026-11-14

S5 Biology: Genetics and Mendelian Inheritance (Paper 4 (error clinic))

This paper corrects ten common errors in Mendelian genetics one by one, covering inverted ratios, heterozygote phenotype, the lost recessive allele, blood-group combinations, the direction of X-linked transmission and the partner used in a test cross.

Direct answers In error-clinic work, state the correct answer and then the reason. Fix dominance first in ratio questions, list gametes first in blood-group questions, and trace the sex chromosome in pedigree questions.

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 20
Difficulty mix Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1
Chapter Chapter: S5 Biology: Genetics and Mendelian Inheritance
Level S3

02 Questions (10 items)

  1. FoundationError clinic: the F2 ratio 3 : 1 was written as three short to one tall. What should it be?
  2. FoundationError clinic: Tt was described as short. What is the correct phenotype?
  3. FoundationError clinic: the recessive allele was said to vanish in F1. What is correct?
  4. IntermediateError clinic: parents IA i and IB i were said to be unable to have a type O child. What is the probability?
  5. IntermediateError clinic: a colour-blind father was said to pass the allele to his sons. What is correct?
  6. IntermediateError clinic: a test cross was said to use a homozygous dominant partner. What is correct?
  7. ChallengeError clinic: from Rr x Rr, 400 of 800 seeds were said to be wrinkled. What is correct?
  8. ChallengeError clinic: AB and O parents were said to be able to have an AB child. What is the probability?
  9. ChallengeError clinic: two tall plants were assumed to share one genotype. What is correct?
  10. Error redoError clinic: Tt x tt was said to give a 3 : 1 ratio. What ratio and count are correct?

03 Answers and one-line notes

# Answer One-line note
1 Three tall to one short. The dominant class is the larger one in F2.
2 Tt is tall. T is dominant, so one dominant allele is enough.
3 The recessive allele remains present but is not expressed. A heterozygote carries the recessive allele, which reappears in F2.
4 They can, with probability one quarter, that is 25 percent. Each parent can pass i, and ii appears once in four combinations.
5 No, a father gives sons only Y; the X-linked allele goes to his daughters. Sons receive X from the mother, so a carrier mother is needed for a colour-blind son.
6 Use a homozygous recessive partner such as tt. The recessive parent masks nothing, so offspring phenotypes reveal the unknown gametes.
7 200 seeds. Wrinkled seeds take one quarter, and 800 divided by 4 is 200.
8 Zero percent, a type AB child is impossible. The O parent carries only i, so no child can receive a second codominant allele.
9 Not necessarily, they may be TT or Tt. A heterozygote and a dominant homozygote look the same, so a test cross is needed.
10 1 : 1, so about 50 of 100 plants are short. A heterozygote crossed with a recessive homozygote gives two genotype classes in equal numbers.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

Sort reproduction questions by place and order first: the testes make sperm, the ovaries make eggs, fertilisation happens in the oviduct and implantation in the uterus, while the placenta and umbilical cord carry nutrients and oxygen; for cycle questions draw the days on one timeline and remember the fertile window runs about three days before and one day after ovulation.Tutor Registration →

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