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DSE Biology | The kidney and osmoregulation: filtration, reabsorption, ADH and negative feedback

DSE Biology | The kidney and osmoregulation: filtration, reabsorption, ADH and negative feedback

  • 2026-11-04

Students can recite that ADH makes urine more concentrated, but cannot trace the line from plasma osmotic pressure to the collecting duct. This lesson turns negative feedback into one arrow pointing backwards.

Objectives — By the end students can: 1) place filtration, reabsorption and secretion in the nephron; 2) calculate daily filtrate volume and the percentage reabsorbed; 3) explain ADH negative feedback from osmotic pressure to urine concentration; 4) compare urine volume and concentration after dehydration and after drinking a lot of water.

01 Prerequisites (3-minute check)

If any of these fails, fix it before the lesson starts.

Skill Quick check Pass mark
Osmosis Which way water moves From higher to lower water potential
Active transport How glucose is reabsorbed Active transport
Negative feedback How body temperature is held steady A deviation triggers the opposite change

02 Lesson flow (60 minutes)

Time Stage Tutor does Student does
0-8 min Three processes Filtration, reabsorption, secretion Name the site of each
8-20 min Filtration Blood pressure pushes water and small solutes into the capsule Cells and protein stay
20-34 min Reabsorption arithmetic 180 litres of filtrate, 1.5 litres of urine Get 99.2 percent
34-46 min ADH feedback Hypothalamus, pituitary, collecting duct Draw the return arrow
46-54 min Two situations Dehydration against heavy drinking Fill a comparison table
54-60 min Exit check Three questions collected and marked Independent work

03 Teaching script (read it out)

Scene 1: Three processes: fix the positions first

Filtration happens in the glomerulus and Bowman capsule: high blood pressure forces water, glucose, urea and ions into the capsule while cells and large proteins stay in the blood. Reabsorption happens in the proximal tubule, where glucose and amino acids are recovered completely by active transport and water follows by osmosis. Secretion happens in the distal tubule, where excess hydrogen ions and drugs are actively moved into the tubule. Draw one tube on the board, write one verb at each site, and afterwards ask only which segment a process belongs to.
At 125 cubic centimetres a minute the daily filtrate is 125 times 60 times 24 divided by 1 000, which is 180 litres. With about 1.5 litres of urine the reabsorption rate is (1 minus 1.5 over 180) times 100, which is 99.2 percent. Plasma glucose is about 1 gram per litre, so 180 grams are filtered daily; none appears in normal urine, which means 100 percent is reabsorbed. Ask what appears in urine once blood glucose exceeds the transport maximum: glucose, which is the basis of diabetes screening.

ADH feedback: dehydration raises plasma osmotic pressure, the hypothalamus detects it, the posterior pituitary releases ADH, the distal tubule and collecting duct become more permeable to water, water is reabsorbed, urine becomes small in volume and concentrated, and osmotic pressure falls back. Drinking a lot of water reverses all of it, with ADH falling and daily urine rising from about 0.5 litre to 15 litres, a 30-fold difference. Have students draw the loop as arrows and label each one rising or falling.

04 Question types and worked steps

Type Example Steps Answer
Calculation Daily filtrate and reabsorption Rate times time, then divide by urine volume 180 litres and 99.2 percent
Explanation How ADH changes urine volume From osmotic pressure to duct permeability Dehydration gives small concentrated urine
Comparison Urine in two situations Compare volume, concentration and ADH 15 against 0.5 litres
Prediction What never appears in filtrate Check molecule size and blood cells Protein and red cells
Sanity check (teach this): A reabsorption percentage must lie between 0 and 100, and filtrate volume must far exceed urine volume; otherwise the units are wrong, since cubic centimetres to litres divides by 1 000. Rising ADH always lowers urine volume and raises concentration, never both upwards. Normal urine contains no glucose.

05 Independent practice (3 questions)

Question Answer What to watch
Daily filtrate at 125 cm3 per minute 180 litres Multiply by 60 and 24, divide by 1 000
Reabsorption percentage when urine is 1.5 litres About 99.2 percent One minus urine over filtrate
Glucose filtered daily at 1 gram per litre 180 grams Filtrate volume times concentration
Effect of more ADH on urine volume It falls Higher water permeability in the collecting duct

06 Common mistakes and what to say

Mistake Student writes Say this
Treating filtration as active transport Saying filtration needs energy Filtration is pressure-driven and passive; glucose reabsorption needs energy.
Putting ADH in the wrong place Saying ADH acts on the glomerulus ADH changes water permeability in the distal tubule and collecting duct, not filtration.
Moving volume and concentration together Answering small and dilute urine Less urine means more concentration, because water was reclaimed.
Skipping unit conversion Answering 180 cubic centimetres of filtrate a day 125 is per minute; multiply by 1 440 and divide by 1 000.

07 Homework (paper, section and question numbers)

08 Exit check (last 5 minutes)

Question Answer Decision
Daily filtrate at 125 cm3 per minute 180 litres All three right: move to the nervous system
Effect of rising ADH on urine Less urine, more concentrated One wrong: redraw the feedback loop
Does normal urine contain glucose No Two wrong: restart act one

09 Tutor FAQ

Why reabsorb more than 99 percent?

Filtrate volume far exceeds the water the body needs to keep, so reclaiming it prevents rapid dehydration.

Where is ADH made and released?

Made in the hypothalamus and released from the posterior pituitary.

Why is urea secreted?

Some urea is reabsorbed passively, and the excess is actively secreted so it can be excreted.

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