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S5 Chemistry: Electrolysis – Error Replay (Paper 4)

S5 Chemistry: Electrolysis – Error Replay (Paper 4)

  • 2026-11-12

S5 Chemistry: Electrolysis – Error Replay (Paper 4)

Ten items retraining the common slips in unit conversion and electron counting.

Direct answers Answers in order: 600 C, copper, chlorine, 0.010 mol, 0.20 mol, hydrogen, 21.6 g, about 0.050 mol, carbon oxidised to carbon dioxide, 3600 C.

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 20
Difficulty mix Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1
Chapter Chapter: S5 Chemistry: Electrolysis and Industrial Applications
Level S5

02 Questions (10 items)

  1. FoundationA current of 1.0 A flows for 10 minutes. What is the charge?
  2. FoundationWhat is obtained at the cathode during the electrolysis of copper sulphate solution?
  3. FoundationWhat is obtained at the anode when molten sodium chloride is electrolysed?
  4. IntermediateHow many moles of electrons does 965 C represent?
  5. Intermediate0.40 mol of electrons passes through copper sulphate solution. How many moles of copper deposit?
  6. IntermediateWhat is obtained at the cathode when dilute sulphuric acid is electrolysed?
  7. ChallengeSilver plating passes 0.20 mol of electrons. What mass of silver deposits? (Ag = 108)
  8. ChallengeA current of 4.0 A flows for 1200 s. How many moles of electrons pass?
  9. ChallengeWhy do the carbon anodes wear away during aluminium extraction?
  10. Error redoError replay: a student puts 30 into the formula for 2.0 A and 30 minutes and gets 60 C. What is correct?

03 Answers and one-line notes

# Answer One-line note
1 600 C Ten minutes is 600 seconds, and one ampere for that long gives 600 C.
2 Copper Copper ions are reduced at the cathode and the metal deposits.
3 Chlorine Chloride ions lose electrons at the anode and chlorine molecules form.
4 0.010 mol Dividing by 96500 gives the answer, and 965 is one hundredth of that value.
5 0.20 mol Copper ions take two electrons each, so the number of moles is halved.
6 Hydrogen Hydrogen ions are reduced at the cathode and hydrogen gas is released.
7 21.6 g Silver ions take one electron each, giving 0.20 mol of silver, which is 21.6 g.
8 About 0.050 mol The charge is 4800 C, and dividing by 96500 gives about 0.0497 mol.
9 The carbon is oxidised to carbon dioxide Oxygen produced at the anode reacts with carbon, so the anodes must be replaced regularly.
10 3600 C Time must be in seconds: 30 minutes is 1800 s, and 2.0 A for that long gives 3600 C.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

Write seconds and the electron count before calculating; that removes half the slips.Tutor Registration →

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