S5 Chemistry: Electrolysis – Error Replay (Paper 4)
Ten items retraining the common slips in unit conversion and electron counting.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S5 Chemistry: Electrolysis and Industrial Applications |
| Level | S5 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 600 C | Ten minutes is 600 seconds, and one ampere for that long gives 600 C. |
| 2 | Copper | Copper ions are reduced at the cathode and the metal deposits. |
| 3 | Chlorine | Chloride ions lose electrons at the anode and chlorine molecules form. |
| 4 | 0.010 mol | Dividing by 96500 gives the answer, and 965 is one hundredth of that value. |
| 5 | 0.20 mol | Copper ions take two electrons each, so the number of moles is halved. |
| 6 | Hydrogen | Hydrogen ions are reduced at the cathode and hydrogen gas is released. |
| 7 | 21.6 g | Silver ions take one electron each, giving 0.20 mol of silver, which is 21.6 g. |
| 8 | About 0.050 mol | The charge is 4800 C, and dividing by 96500 gives about 0.0497 mol. |
| 9 | The carbon is oxidised to carbon dioxide | Oxygen produced at the anode reacts with carbon, so the anodes must be replaced regularly. |
| 10 | 3600 C | Time must be in seconds: 30 minutes is 1800 s, and 2.0 A for that long gives 3600 C. |
Write seconds and the electron count before calculating; that removes half the slips.Tutor Registration →
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