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S5 Chemistry: Enthalpy Change and Energy (Paper 2: Intermediate)

S5 Chemistry: Enthalpy Change and Energy (Paper 2: Intermediate)

  • 2026-11-12

S5 Chemistry: Enthalpy Change and Energy (Paper 2: Intermediate)

Ten intermediate items: standard conditions, per-mole conversion, the direction of calorimetry error, enthalpy of solution, bond energy method and back-calculation of mass, with answers and notes.

Direct answers Answers in order: 298 K and 1 atm, -286 kJ mol-1, one mole and about -57 kJ mol-1, too small, 12.6 kJ, -44.1 kJ mol-1, -93 kJ mol-1, copper, 8.0 g, activation energy is still needed.

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 20
Difficulty mix Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1
Chapter Chapter: S5 Chemistry: Enthalpy Change and Energy
Level S5

02 Questions (10 items)

  1. FoundationUnder what conditions is a standard molar enthalpy change measured?
  2. FoundationFor 2H2 + O2 -> 2H2O the enthalpy change is -572 kJ mol-1. What is the enthalpy change per mole of hydrogen burned?
  3. FoundationThe enthalpy of neutralisation refers to the formation of how many moles of water, and what is the rough value for dilute strong acid and strong alkali?
  4. IntermediateIf some heat escapes to the air during calorimetry, is the calculated magnitude of ΔH too large or too small?
  5. IntermediateIn a combustion experiment 250 cm3 of water rises by 12.0 °C. How much heat does the water absorb?
  6. Intermediate4.0 g of sodium hydroxide (molar mass 40 g mol-1) dissolves in 100 g of water and the temperature rises by 10.5 °C. Find the molar enthalpy change of solution.
  7. ChallengeGiven bond energies N=N 945, H-H 436 and N-H 391 kJ mol-1, find ΔH for N2 + 3H2 -> 2NH3.
  8. ChallengeWater has a specific heat capacity of 4.2 J g-1 K-1 and copper 0.385 J g-1 K-1. Equal masses absorb equal heat: which warms more?
  9. ChallengeThe enthalpy change of combustion of methane is -890 kJ mol-1. What mass of methane (molar mass 16 g mol-1) must burn to release 445 kJ?
  10. Error redoA student claims an exothermic reaction needs no activation energy and finishes instantly on contact. What is wrong?

03 Answers and one-line notes

# Answer One-line note
1 298 K and 1 atm, with each substance in its standard state Standard conditions are 298 K and 1 atm, which makes values comparable.
2 -286 kJ mol-1 The equation releases 572 kJ for 2 mol of hydrogen, so dividing by 2 gives -286 kJ mol-1.
3 One mole of water, about -57 kJ mol-1 It is defined per mole of liquid water formed, and dilute strong acid with strong alkali gives about -57 kJ mol-1 because ionisation is complete.
4 Too small The water absorbs less heat, so q underestimates the heat released and the magnitude of ΔH comes out too small.
5 12.6 kJ q = 250 times 4.2 times 12.0 gives 12600 J, which is 12.6 kJ.
6 -44.1 kJ mol-1 0.10 mol dissolves in 100 g of water, q = 100 times 4.2 times 10.5 gives 4410 J, and dividing by 0.10 gives -44.1 kJ mol-1.
7 -93 kJ mol-1 Breaking bonds needs 945 plus 3 times 436, which is 2253, and forming bonds releases 6 times 391, which is 2346; the difference is -93 kJ mol-1.
8 Copper, because its specific heat capacity is smaller A smaller specific heat capacity means less heat is needed per kelvin, so copper shows the larger temperature rise.
9 8.0 g 445 divided by 890 gives 0.50 mol, and times 16 that is 8.0 g.
10 It still needs activation energy first, so the rate is not infinitely fast Activation energy is the initial barrier and is independent of whether the reaction is exothermic, so exothermic reactions can still be slow.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

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