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S5 Chemistry: Enthalpy Change and Energy (Paper 4: Misconception Drill)

S5 Chemistry: Enthalpy Change and Energy (Paper 4: Misconception Drill)

  • 2026-11-12

S5 Chemistry: Enthalpy Change and Energy (Paper 4: Misconception Drill)

Ten items on the commonest enthalpy misconceptions: which mass to use, steam versus liquid water, breaking and forming bonds, molar conversion and units, with answers and notes.

Direct answers Answers in order: 5.0 °C, total solution mass, too small, breaking is endothermic and forming is exothermic, reactants by 300 kJ mol-1, -440 kJ mol-1, use the water formed, 25 g, endothermic with positive DH, it should be kJ mol-1.

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 20
Difficulty mix Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1
Chapter Chapter: S5 Chemistry: Enthalpy Change and Energy
Level S5

02 Questions (10 items)

  1. Foundation200 g of water absorbs 4200 J of heat. By how many °C does its temperature rise?
  2. FoundationIn q = mcDT for a neutralisation, what mass should m be?
  3. FoundationIf the water formed leaves as steam when measuring an enthalpy of combustion, does the magnitude of ΔH come out too large or too small?
  4. IntermediateIs bond breaking endothermic or exothermic, and what about bond forming?
  5. IntermediateA reaction has ΔH equal to -300 kJ mol-1. Which has the higher enthalpy, and by how much?
  6. IntermediateBurning 0.10 mol of a fuel releases 44.0 kJ of heat. Should the molar enthalpy change be written as -44 or -440 kJ mol-1?
  7. ChallengeIn a neutralisation calculation, which amount should be used: acid, alkali, or water formed?
  8. ChallengeTaking the density of a solution as 1 g cm-3, what is the mass of 25 cm3 of it?
  9. ChallengeThe temperature falls after two solutions are mixed. Is the reaction exothermic or endothermic, and what is the sign of ΔH?
  10. Error redoA student writes the unit of a molar enthalpy change as kJ. What is wrong?

03 Answers and one-line notes

# Answer One-line note
1 5.0 °C From q = mcDT, DT is 4200 divided by 200 times 4.2, which gives 5.0 °C.
2 The total mass of the mixed solution, including the solute The whole solution warms up, so counting only the water underestimates the heat released.
3 Too small, because the heat of condensation is lost Steam carries away the enthalpy of vaporisation, so the measured heat release is too low.
4 Breaking is endothermic and forming is exothermic Energy must be supplied to pull atoms apart, whereas forming a new bond releases energy.
5 The reactants, by 300 kJ mol-1 A negative ΔH means the products are lower in enthalpy, the difference of 300 kJ mol-1 being released as heat.
6 -440 kJ mol-1 The molar value is per mole, so 44.0 divided by 0.10 gives 440, that is -440 kJ mol-1.
7 The moles of water formed, after identifying the limiting reagent The enthalpy of neutralisation is defined per mole of water formed, so the limiting reagent decides the amount to use.
8 25 g A density of 1 g cm-3 means 1 g per cm3, so 25 cm3 has a mass of 25 g.
9 Endothermic, so ΔH is positive A fall in temperature means heat is taken from the solution, which is endothermic and gives a positive ΔH.
10 It should be kJ mol-1; kJ is a quantity of heat, not a molar value A molar enthalpy is quoted per mole, so without mol-1 the unit does not describe energy per mole.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

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