S5 Chemistry | Ionic Reactions and Precipitation prep guide (for tutors) | Solubility rules and limiting reagents
- 2026-11-01
Students copy every ion into their ionic equations, and they call any white solid AgCl. This lesson fixes two things: which ions actually change, and which ion runs out first after mixing.
01 Prerequisites (3-minute check)
If any of these fails, fix it before the lesson starts.
| Skill | Quick check | Pass mark |
|---|---|---|
| Moles n = cV | How many moles are in 25.0 cm3 of 0.100 M solution? | 2.50e-3 mol: convert cm3 to dm3 first |
| Balancing equations | In Ag+ + Cl- -> AgCl, is charge balanced? | Yes: +1 -1 = 0 on each side |
| Molar mass | What is the molar mass of AgCl? | 143.32 g/mol |
02 Lesson flow (50 minutes)
| Time | Stage | Tutor does | Student does |
|---|---|---|---|
| 0-6 min | Opening question | NaCl and AgNO3 are poured together: which two ions actually react? | Two ions named |
| 6-12 min | Prerequisite check | n = cV, balancing, molar mass | All three correct before moving on |
| 12-22 min | Act 1 | Solubility rules and the four common precipitates | A four-row table |
| 22-30 min | Act 2 | Net ionic equations: drop spectators, balance charge | Ag+ + Cl- -> AgCl(s) |
| 30-42 min | Act 3 | Limiting reagent: Pb2+ with I-, remaining concentrations | [Pb2+] = 0.075 M |
| 42-47 min | Worked examples | One start-up routine per question type | Students copy the routine |
| 47-50 min | Exit check | Three questions marked on the spot | Answered independently |
03 Teaching script (read it out)
Scene 1: Solubility rules: build the table first
Two worked examples: 25.0 cm3 of 0.100 M AgNO3 holds 2.5 mmol of Ag+, so complete precipitation gives 0.358 g of AgCl. For BaCl2, 20.0 cm3 of 0.150 M holds 3.0 mmol of Ba2+, which needs 30.0 cm3 of 0.100 M Na2SO4 and gives 0.70 g of BaSO4.
Teach the order: check solubility first, then concentration after mixing. Never start by writing an equation. Warn about PbCl2 dissolving in hot water, which is a favourite trap.
Task: decide whether mixing KNO3 and NaCl gives a precipitate, and give the reason (no: everything is soluble).
Scene 2: Net ionic equations: keep only what changes
Three habits: label the precipitate (s); confirm total charge is equal on both sides, here +1 -1 = 0; and split only strong electrolytes, never weak acids, water or solids. Ask students to read the charge balance aloud after every equation they write.
Task: write the net ionic equation for BaCl2 + Na2SO4 and circle the spectator ions (Ba2+ + SO4 2- -> BaSO4(s); spectators Na+ and Cl-).
Scene 3: Limiting reagent: moles first, coefficients second
Left over: 7.5 mmol of Pb2+ in 100 cm3, so 0.075 M; K+ is a spectator at 0.050 M and NO3- at 0.200 M. Finish with the electroneutrality check: 2 x 0.075 + 0.050 = 0.200, which matches [NO3-]. Make this check routine; it catches errors faster than recalculating.
Task: if 100 cm3 of 0.100 M KI is used instead, what mass of PbI2 forms and what is the remaining [Pb2+]? (2.3050 g and 0.0333 M.)
04 Question types and worked steps
| Type | Example | Steps | Answer |
|---|---|---|---|
| Will it precipitate? | Apply solubility rules | Solubility first, then ion pairing | Four-row table |
| Net ionic equation | Split strong electrolytes, drop spectators | Label (s) and check charge | Ag+ + Cl- -> AgCl(s) |
| Mass of precipitate | n = cV, then multiply by molar mass | cm3 to dm3 before multiplying | 0.70 g |
| Limiting reagent and leftovers | Compare moles with the coefficient ratio | Divide by total volume, verify electroneutrality | [Pb2+] = 0.075 M |
05 Independent practice (3 questions)
| Question | Answer | What to watch |
|---|---|---|
| 0.050 dm3 of 0.20 M CaCl2 reacts with excess Na2CO3. What mass of CaCO3 forms (M = 100.09)? | 1.00 g | 0.010 mol x 100.09 |
| Write the net ionic equation for Pb(NO3)2 + 2KI | Pb2+ + 2I- -> PbI2(s) | K+ and NO3- are spectators |
| 0.10 mol Ba2+ meets 0.15 mol SO4 2-. Which is limiting, and how much remains? | Ba2+ limiting; 0.05 mol SO4 2- left | 1:1 reaction, subtract directly |
06 Common mistakes and what to say
| Mistake | Student writes | Say this |
|---|---|---|
| Keeping Na+ and NO3- in the ionic equation | Believing every ion must appear | “Na+ and NO3- are spectators from start to finish; delete them.” |
| Omitting the (s) label | Focusing only on balancing | “A solid needs (s); without it the answer still looks dissolved.” |
| Judging the limiting reagent by concentration | Assuming the stronger solution must be in excess | “High concentration is not high amount: multiply by the volume.” |
| Dividing leftover moles by the original volume | Forgetting the volume grows on mixing | “Two beakers make one total volume: 100 cm3, not 50.” |
07 Homework (paper, section and question numbers)
- Secondary Chemistry chapter index (moles, bonding, periodic table, acids, redox, electrolysis) — Do the moles chapter first, then questions 2, 4 and 6 (precipitate mass and limiting reagent)
- Secondary prep guides overview (all subjects) — Revise in subject order
08 Exit check (last 5 minutes)
| Question | Answer | Decision |
|---|---|---|
| Which chloride is the exception to the soluble-chloride rule? | AgCl (and PbCl2) | Wrong means Act 1 again |
| Which ions are removed from a net ionic equation? | Spectators that appear unchanged on both sides | Wrong means Act 2 again |
| Do you judge the limiting reagent by concentration or moles? | Moles: concentration times volume | Two or more wrong means back to Act 3 |
09 Tutor FAQ
Which year is this for?
S5, the reactions and stoichiometry unit of HKDSE chemistry; S4 can meet it in the second term.
Must every solubility rule be memorised?
Five spines: Na K NH4 soluble, nitrates soluble, chlorides minus Ag and Pb, sulfates minus Ba Pb Ca, most carbonates insoluble.
Where do marks usually leak?
Units (cm3 versus dm3) and the total volume; get either wrong and everything after fails.
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A TutorZone lesson-prep guide. Written by the TutorZone team; questions and lesson flow are original and are not taken from any school or publisher material.


