S5 Chemistry Rates of Reaction, Paper 4: average rate, temperature effect and molar volume
- 2026-11-02
S5 Chemistry Rates of Reaction, Paper 4: average rate, temperature effect and molar volume
Ten graded items on gas collection rates, temperature doubling, catalysts, surface area and a molar volume conversion, each with an answer.
Focus Rate is change over time, ten degrees roughly doubles it, a catalyst lowers activation energy and molar volume links moles to volume.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 25 |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: S5 Chemistry: Rates of Reaction |
| Level | Four basic, three advanced, two challenge and one error-repair item |
02 Questions (10 items)
- Foundation96 cm^3 of hydrogen is collected in 40 s. What is the average rate?
- FoundationRate roughly doubles for every 10 C rise. By what factor does it change from 25 C to 55 C?
- FoundationHow does a catalyst speed up a reaction?
- FoundationEqual masses of limestone powder and limestone chips react with acid of the same concentration. Which is faster?
- IntermediateIn the first 30 s the concentration of a reactant falls from 0.80 to 0.50 mol dm^-3. What is the average rate?
- IntermediateIn the same reaction, how many times faster is the run at 60 C than the run at 20 C?
- IntermediateThe volume against time curve becomes flatter and flatter. What does that show?
- Challenge0.240 g of magnesium ribbon (24 g mol^-1) reacts completely with excess dilute acid. What volume of hydrogen is collected at room temperature (24 dm^3 mol^-1)?
- ChallengeRun A finishes in 20 s and run B in 80 s. What is the ratio of their average rates, A to B?
- Error redoError repair: a student writes that a flat curve means the reaction has stopped and particles no longer collide. What is wrong?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | 2.4 cm^3 s^-1 | Rate is volume over time, so 96 divided by 40 gives 2.4. |
| 2 | Eight times | A rise of 30 C is three steps of 10 C, and doubling three times gives two to the power three. |
| 3 | It provides an alternative route of lower activation energy | A catalyst offers a route with a lower activation energy, so a larger fraction of collisions succeed and the rate rises. |
| 4 | The powder | The powder has a much larger surface area, so more particles meet the acid at once and the collision frequency is higher. |
| 5 | 0.0100 mol dm^-3 s^-1 | The concentration falls by 0.30, which over 30 s gives 0.0100. |
| 6 | Sixteen times faster | The gap of 40 C is four steps of 10 C, so the hotter run is sixteen times faster. |
| 7 | The reactant concentration is low, the rate has slowed and the reaction is nearly complete | A flattening curve means less gas is formed each second, not that the reaction has stopped completely. |
| 8 | 240 cm^3 | The magnesium is 0.0100 mol and each mole gives one mole of hydrogen, so 0.0100 times 24 dm^3 is 0.240 dm^3. |
| 9 | 4 : 1 | The shorter run is faster, and 80 divided by 20 is 4, so the first run is four times as fast. |
| 10 | The particles still collide, but the low concentration makes collisions rare | Near the end little reactant is left, so collisions become rare and the curve flattens; the particles still collide. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
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