S5 Maths: Dispersion and Standard Deviation: Paper 1 (Basics)
Ten items on the range, mean, median and quartiles, fixing the basic idea of dispersion first.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S5 Maths: Dispersion and Standard Deviation |
| Level | Basics |
| # | Answer | One-line note |
|---|---|---|
| 1 | Range = 12 | Range = largest value – smallest value = 15 – 3 = 12. |
| 2 | Mean = 8 | The seven values add up to 56, and 56 / 7 = 8. |
| 3 | Median = 7 | With seven values in order, the fourth value is the median. |
| 4 | Q1 = 5 | The middle of the lower three values 3, 5, 6 is 5. |
| 5 | Q3 = 11, inter-quartile range = 6 | The middle of the upper three values 9, 11, 15 is 11, and 11 – 5 = 6. |
| 6 | Inter-quartile range = 8 | Q1 = 12 and Q3 = 20, so 20 – 12 = 8. |
| 7 | Standard deviation = 3.74 | The standard deviation is the square root of the variance, and the square root of 14 is about 3.74. |
| 8 | The inter-quartile range | The range uses only the largest and smallest values, so one extreme value can change it a great deal. |
| 9 | Range 12, inter-quartile range 6 | A shift of all values leaves the gaps between them unchanged. |
| 10 | Correct | A standard deviation of 0 means all values are equal, so the range is bound to be 0. |
Write the mean first, then list each squared deviation; that keeps the working clean.Tutor Registration →
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