S5 Maths Indices and Logarithms Paper 3: Challenge
- 2026-11-09
S5 Maths Indices and Logarithms Paper 3: Challenge
Ten original exponential equation items, each with an answer and a one-line explanation.
Direct answers Items 1-3 use equal bases and log equations, 4-6 substitute y for a to the x to reach a quadratic, 7-8 simplify logs and check both roots, 9 applies compound interest, and item 10 clears up splitting a power.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S5 Maths: Indices and Logarithms |
| Level | S5 |
02 Questions (10 items)
- FoundationSolve 3 to the power (x plus 1) equals 27 to the power (x minus 1).
- FoundationSolve 9 to the x equals 27.
- FoundationSolve log base 2 of x plus log base 2 of (x minus 2) equals 3.
- IntermediateSolve 4 to the x minus 5 times 2 to the x plus 4 equals 0.
- IntermediateSolve 5 to the power 2x minus 6 times 5 to the x plus 5 equals 0.
- IntermediateSolve 2 to the power x squared equals 8 to the x, where x is not 0.
- ChallengeSolve log base 10 of x equals twice log base 10 of 3 plus log base 10 of 2.
- ChallengeSolve 3 to the power 2x minus 10 times 3 to the x plus 9 equals 0.
- ChallengeA deposit earns 5 per cent compound interest a year, so the amount is P times 1.05 to the n. What is the least whole number of years for the money to double?
- Error redoA pupil rewrites 2 to the power (x plus 1) as 2 to the x plus 2. What is the correct form?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | x = 2 | Since 27 is 3 cubed, x + 1 = 3x – 3, which gives 4 = 2x and x = 2. |
| 2 | x = 3/2, that is 1.5 | Use base 3 on both sides: 2x = 3, so x is 1.5. |
| 3 | x = 4 | Combine to x(x – 2) = 8, giving roots 4 and -2; only 4 keeps both arguments positive. |
| 4 | x = 0 or x = 2 | Let y be 2 to the x: y squared minus 5y plus 4 factors into 1 and 4, so x is 0 or 2. |
| 5 | x = 0 or x = 1 | Let y be 5 to the x: the quadratic gives y equal to 1 or 5, so x is 0 or 1. |
| 6 | x = 3 | Since 8 to the x is 2 to the 3x, x squared equals 3x, so x is 0 or 3, and 0 is excluded. |
| 7 | x = 18 | The right side is the log of 9 times 2, that is the log of 18, so x is 18. |
| 8 | x = 0 or x = 2 | Let y be 3 to the x: the roots are 1 and 9, so x is 0 or 2. |
| 9 | 15 years | We need 1.05 to the n to reach 2, so n is at least 14.2 and the answer is 15; 14 years gives only about 1.98 times. |
| 10 | 2 times 2 to the x | Adding indices multiplies: 2 to the x plus 1 is 2 times 2 to the x, and the 2 cannot be pulled out as a separate term. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
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