S5 Mathematics: Permutations and Combinations Practice Paper 2
- 2026-11-03
S5 Mathematics: Permutations and Combinations Practice Paper 2
Set two uses fresh numbers: arrangements of five people, choosing three of seven and three distinct posts to fix factorial against C(n,r), then ten choose four, mixed groups and a block method, then two unlabelled groups and the repeated letters of MISSISSIPPI, ending with the error of answering 21 instead of 42.
Quick answer 120, 35, 336, 24, 210, 36, 240, 126, 34 650 and 42.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | 25 minutes |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: S5 Mathematics: Permutations and Combinations – Tutor Lesson Plan |
| Level | S5 |
02 Questions (10 items)
- FoundationFive students stand in a line. How many different orders are possible?
- FoundationHow many ways are there to choose 3 books from 7 different books?
- FoundationFrom 8 people, pick a chairperson, a vice-chairperson and a secretary, all different. How many outcomes?
- FoundationHow many arrangements are there of the four letters A, B, C and D?
- IntermediateHow many 4-person teams can be formed from 10 students?
- IntermediateFrom 4 boys and 4 girls, choose 2 boys and 2 girls. How many combinations?
- IntermediateSix people queue up with A and B standing next to each other. How many orders are possible?
- ChallengeTen people are split into two groups of 5, with the groups unlabelled. How many ways?
- ChallengeHow many distinct arrangements are there of all 11 letters in MISSISSIPPI?
- Error redoFrom 7 people, choose 2 where one becomes class monitor and one becomes deputy. How many arrangements?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | 120 orders | Multiply 5 x 4 x 3 x 2 x 1, which is 5 factorial, giving 120. |
| 2 | 35 ways | Order does not matter here, so use C(7,3), which is 7 x 6 x 5 divided by 6, giving 35. |
| 3 | 336 outcomes | That is 8 x 7 x 6, because the three roles differ and order matters. |
| 4 | 24 arrangements | It is 4 factorial, that is 4 x 3 x 2 x 1 = 24. |
| 5 | 210 teams | C(10,4) is 10 x 9 x 8 x 7 divided by 24, giving 210. |
| 6 | 36 combinations | Take C(4,2) times C(4,2), which is 6 x 6 = 36. |
| 7 | 240 orders | Treat A and B as one block so there are 5! orders, times 2 for swapping them, giving 240. |
| 8 | 126 ways | That is C(10,5) divided by 2!, which is 252 divided by 2, giving 126. |
| 9 | 34 650 arrangements | Divide 11! by 4! x 4! x 2!, which is 39 916 800 divided by 1 152, giving 34 650. |
| 10 | 42 arrangements | The posts differ, so order matters and the answer is 42, not the 21 of C(7,2). |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
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