S5 Maths: Variation: Paper 2 (Intermediate)
Ten items on inverse variation: multiply to get k, then handle roots and real contexts.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S5 Maths: Variation |
| Level | Intermediate |
| # | Answer | One-line note |
|---|---|---|
| 1 | 3 | k = 6 x 4 = 24, so y = 24 / 8 = 3. |
| 2 | 2 | k = 10 x 3 = 30, and 15x = 30 gives x = 2. |
| 3 | 9 days | Total work is 12 x 6 = 72 worker-days, and 72 / 8 = 9 days. |
| 4 | 1 | k = 4 x 9 = 36, so y = 36 / 36 = 1. |
| 5 | 3 hours | The distance is 60 x 4 = 240 km, and 240 / 80 = 3 hours. |
| 6 | 6 | k = 24, and x becomes 4, so y = 24 / 4 = 6, which is double. |
| 7 | 5 | k = 2.5 x 8 = 20, and 4x = 20 gives x = 5. |
| 8 | 12 hours | 6 x 8 = 48 tap-hours, and 48 / 4 = 12 hours. |
| 9 | 4 | k = 6 x 2 = 12, so y = 12 / 3 = 4. |
| 10 | Inverse variation needs multiplication: k = 40, so y = 5 | For y = k / x, k comes from multiplying x and y; dividing belongs to direct variation. |
For each wrong item, write whether you multiplied or divided to get k.Tutor Registration →
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