S5 Physics Induction and Transformers, Paper 3: Faraday law and transmission
- 2026-11-02
S5 Physics Induction and Transformers, Paper 3: Faraday law and transmission
Covers transformer turns and current, induced e.m.f. from flux change, transmission current and I squared R loss, and efficiency in ten graded items.
Focus Decide step-up or step-down first, then use the turns ratio; in transmission questions always find the current from P equals VI before the I squared R loss.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 25 |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: S5 Physics: Electromagnetic Induction and Transformers |
| Level | Four basic, three advanced, two challenge and one error-repair item |
02 Questions (10 items)
- FoundationA transformer has 1000 primary turns and 50 secondary turns with 220 V input. Find the output voltage.
- FoundationA transformer has 200 primary turns and 1000 secondary turns with 12 V input. Find the output voltage.
- FoundationAn ideal transformer takes 220 V at 0.5 A and gives 11 V. Find the output current.
- FoundationThe flux through a 500 turn coil falls from 0.004 Wb to zero in 0.02 s. Find the induced e.m.f.
- IntermediateA power station sends 100 kW. Find the current at 11 kV and at 1 kV.
- IntermediateA transmission line has a total resistance of 2 ohm. Find the loss at 100 A and at 9.1 A.
- IntermediateA transformer is 90 per cent efficient with 500 W input and 22 V output. Find the output power and current.
- ChallengeThe flux through a 200 turn coil rises from 0.015 Wb to 0.055 Wb in 0.1 s. Find the average induced e.m.f.
- ChallengeThe same 100 kW is sent through a 2 ohm line at 5 kV and at 50 kV. Find both losses and the ratio.
- Error redoA student thinks a step-up transformer multiplies power and claims 22000 W from a 220 V, 10 A input. What is the correct secondary power?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | 11 V | The turns ratio sets the voltage ratio, so 220 times 50 over 1000 gives 11 V. |
| 2 | 60 V | This is a step-up transformer, so 12 times 1000 over 200 gives 60 V. |
| 3 | 10 A | An ideal transformer keeps power constant, so 110 watts at 11 volts gives 10 A. |
| 4 | 100 V | Faraday law gives 500 times 0.004 over 0.02, that is 100 V. |
| 5 | 9.1 A and 100 A | Current is power over voltage, giving about 9.1 A at 11 kV and 100 A at 1 kV. |
| 6 | 20000 W and about 165 W | Loss is I squared R, so 100 squared times 2 is 20000 watts, while 9.1 squared times 2 is only about 165 watts. |
| 7 | 450 W and 20.5 A | Output power is 450 watts, so the current is 450 over 22, about 20.5 A. |
| 8 | 80 V | The flux changes by 0.040 webers, so 200 times 0.04 over 0.1 gives 80 V. |
| 9 | 800 W and 8 W, a factor of 100 | At 5 kV the current is 20 A and the loss 800 watts; at 50 kV the current is 2 A and the loss 8 watts, a hundredfold saving. |
| 10 | 2200 W | An ideal transformer changes voltage and current but not power, so the secondary power is still 2200 watts. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
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