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S5 Physics: Momentum and Collisions – Foundation Practice (10 Questions)
S5 Physics: Momentum and Collisions – Foundation Practice (10 Questions)
Get fluent with p equals mv: 2 kg at 3 m/s gives 6 kg m/s, 0.5 kg at 8 m/s gives 4, momentum 12 at 4 m/s means 3 kg, a 1 500 kg car at 20 m/s gives 30 000, adding momenta in one direction gives 24 and subtracting opposite ones gives 10.
Quick answer Momentum 2 kg at 3 m/s is 6; 0.5 kg at 8 m/s is 4; 12 over 4 gives 3 kg; 1 500 kg at 20 m/s is 30 000; 24 over 6 is 4 m/s; same direction adds to 24 and opposite gives 10; a bounce changes momentum by 5; slowing from 12 to 4 changes it by minus 24; a reversal is 12, not zero.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | about 20 minutes |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: S5 Physics | Momentum and Collisions: Conservation, Impulse and Collision Types |
| Level | S5 |
02 Questions (10 items)
- FoundationA 2 kg ball rolls east at 3 m/s. What is its momentum?
- FoundationA 0.5 kg tennis ball flies off at 8 m/s. What is its momentum?
- FoundationAn object has momentum 12 kg m/s and speed 4 m/s. What is its mass?
- FoundationA 1 500 kg car travels at 20 m/s. What is its momentum?
- IntermediateMomentum is 24 kg m/s for a mass of 6 kg. What is the velocity?
- IntermediateA 3 kg ball moves east at 4 m/s and a 2 kg ball at 6 m/s the same way. What is the total momentum?
- IntermediateA 4 kg body moves east at 5 m/s while a 2 kg body moves west at 5 m/s. What is the total momentum?
- ChallengeA 0.2 kg ball hits a wall at 15 m/s and bounces back at 10 m/s. What is the size of the momentum change?
- ChallengeA 3 kg body slows from 12 m/s to 4 m/s. What is its momentum change?
- Error redoFor a 2 kg ball changing from 3 m/s east to 3 m/s west a student answers that the momentum change is zero. What is the correct value and where is the error?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | 6 kg m/s east, because momentum is mass times velocity. | Momentum is a vector, so give the direction together with the number. |
| 2 | 4 kg m/s, since 0.5 times 8 is 4. | A small mass can still carry large momentum when the speed is high. |
| 3 | 3 kg, because mass is momentum divided by velocity, 12 over 4. | The three forms interchange: p equals mv, m equals p over v, v equals p over m. |
| 4 | 30 000 kg m/s. | A heavy slow object can carry far more momentum than a bullet. |
| 5 | 4 m/s, since velocity is momentum divided by mass. | Check it back with p equals mv, number and unit together. |
| 6 | 24 kg m/s east, from 12 plus 12. | Same direction means simple addition, since momentum adds like a vector. |
| 7 | 10 kg m/s east, from 20 minus 10. | Fix a positive direction first, so the westward momentum carries a minus sign. |
| 8 | 5 kg m/s, because a reversal means adding: 0.2 times 15 plus 10. | For a bounce the changes add rather than subtract; that is the usual trap. |
| 9 | Minus 24 kg m/s, falling from 36 to 12. | The minus sign means momentum dropped, that is a change opposite to the motion. |
| 10 | The change is 12 kg m/s west, since 2 times minus 3 minus 3 is minus 12. A reversal cannot count as zero. | Equal speeds do not mean unchanged momentum; turning round changes it. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
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