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Resistance and Circuits Paper 4: Error Clinic

Resistance and Circuits Paper 4: Error Clinic

  • 2026-11-11

Resistance and Circuits Paper 4: Error Clinic

This paper targets the four most common slips: series voltage division, rated versus actual values, energy-cost units, and parallel simplification.

Direct answers Answers and explanations for all ten questions

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 20
Difficulty mix Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1
Chapter Chapter: DSE Physics Resistance and Circuits
Level Paper 4 (error clinic)

02 Questions (10 items)

  1. FoundationA 12 V battery is connected across a 3 ohm resistor. Find the current.
  2. FoundationTwo resistors of 10 ohms and 15 ohms are in parallel. Find the equivalent resistance.
  3. FoundationA 6 ohm resistor carries a current of 0.5 A. Find the power it dissipates.
  4. IntermediateA uniform 2 m resistance wire has a resistance of 8 ohms. Cut it to 0.5 m and find the new resistance.
  5. IntermediateA 12 ohm resistor is in series with two 6 ohm resistors in parallel, across a 12 V supply. Find the total resistance, the current, and the voltage across the parallel block.
  6. IntermediateAn 800 W appliance runs 3 hours a day for 30 days. Find the energy used and the cost at 1.1 dollars per kWh.
  7. ChallengeThree 12 ohm resistors in parallel are connected to a 12 V supply. Find the equivalent resistance and the total current.
  8. ChallengeA lamp is rated 12 V and 24 W. Find its resistance and the actual power when it is run at 9 V.
  9. ChallengeA motor takes in 1 500 J of electrical energy and delivers 1 050 J of mechanical energy. Find the efficiency and the energy lost as heat.
  10. Error redoError clinic: a student claims each of two 6 ohm resistors in series across 12 V gets the full 12 V. Correct the voltage, current and power.

03 Answers and one-line notes

# Answer One-line note
1 4.0 A, from I equals V over R, that is 12 divided by 3. Check the units first, then substitute into the current formula.
2 5.999999999999999 ohms, since one over R equals one tenth plus one fifteenth. A parallel combination is always smaller than its smallest member.
3 1.5 W, from P equals I squared times R. With current and resistance known, P equals I squared R skips the voltage step.
4 2.0 ohms, because resistance falls in proportion to length. With the same material and cross-section, a quarter of the length gives a quarter of the resistance.
5 The parallel block is 3.0 ohms, the total 15.0 ohms, the current 0.8 A and the block voltage 2.4000000000000004 V. Simplify the parallel block first, then add the series part; voltage divides in proportion to resistance.
6 72.00000000000001 kWh costing 79.20000000000002 dollars, from 0.8 kW times 3 hours times 30 days. Convert watts to kilowatts first, or the energy comes out a thousand times too large.
7 4.0 ohms and 3.0 A: identical branches divide the resistance by three, and the branch currents add up. Each branch carries 1 A, so three branches give 3 A as a check.
8 The resistance is 6.0 ohms, and at 9 V the power is 13.5 W. Treat the resistance as fixed: three quarters of the voltage leaves nine sixteenths of the power.
9 70.0 per cent efficient, with 450 J lost as heat. Output plus loss must equal input, which double-checks the efficiency.
10 Each takes only 6.0 V with 1.0 A, so 6.0 W each: voltage divides between equal resistors. Giving the full supply voltage to every component is the classic series mistake.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

Ask first whether the circuit is series or parallel, then whether the figures are rated or actual; those two questions remove most errors.Tutor Registration →

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