S5 Physics: Waves and Sound Practice Paper 2
- 2026-11-01
S5 Physics: Waves and Sound Practice Paper 2
Paper two warms up with v = f lambda, a 250 Hz period and sound in a vacuum, then times thunder at 2.5 s, halves a sonar echo and moves a wave from air into water, before a fixed string fundamental and a 500-vibration count, ending with the wavelength mix-up.
Quick answer 300 m/s, 0.004 s, 0.68 m, a medium is needed, 850 m, 600 m, 3 m, 2.4 m at 150 Hz, 250 Hz at 150 m/s, and a lower frequency.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | 25 minutes |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: S5 Physics: Waves and Sound – Tutor Lesson Plan |
| Level | S5 |
02 Questions (10 items)
- FoundationA wave has frequency 200 Hz and wavelength 1.5 m. Find its speed.
- FoundationWhat is the period of a wave of frequency 250 Hz?
- FoundationSound travels at 340 m/s. Find the wavelength of a 500 Hz note.
- FoundationCan sound travel through a vacuum?
- IntermediateThunder is heard 2.5 s after the lightning is seen (sound speed 340 m/s). How far away did it strike?
- IntermediateA sonar sends ultrasound and receives the echo from the seabed 0.8 s later (sound speed in water 1 500 m/s). Find the depth.
- IntermediateA 500 Hz sound passes from air (340 m/s) into water (1 500 m/s) with the frequency unchanged. Find the wavelength in water.
- ChallengeA string fixed at both ends is 1.2 m long. Find the wavelength of the fundamental, and its frequency if the wave speed is 360 m/s.
- ChallengeA source makes 500 vibrations in 2 s and the wavelength is 0.6 m. Find the frequency and the speed.
- Error redoA student says a longer wavelength means a higher frequency. What is wrong?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | 300 m/s (200 x 1.5) | Wave speed is v = f lambda. |
| 2 | 0.004 s (1 / 250) | The period is T = 1 / f. |
| 3 | 0.68 m (340 / 500) | Rearranging v = f lambda gives lambda = v / f. |
| 4 | No, sound needs a medium | Sound is a vibration of particles, and a vacuum has none. |
| 5 | 850 m (340 x 2.5) | Light arrives almost at once, so the delay measures the sound. |
| 6 | 600 m (1 500 x 0.8 / 2) | The echo travels out and back, so the time covers twice the depth. |
| 7 | 3 m (1 500 / 500) | The frequency is set by the source, while the wavelength follows the speed. |
| 8 | 2.4 m and 150 Hz | Both ends are nodes, so the fundamental is half a wave and the wavelength is twice the length. |
| 9 | 250 Hz and 150 m/s | The frequency is 500 / 2 = 250, so the speed is 250 x 0.6. |
| 10 | In one medium the speed is fixed, so a longer wavelength means a lower frequency | With v fixed in v = f lambda, f and lambda are inversely related. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
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