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S5 Physics: Waves and Sound Practice Paper 4
S5 Physics: Waves and Sound Practice Paper 4
Paper four opens with v = f lambda, a period reciprocal and a tuning fork count, then covers the need for a medium, thunder at 5 s, a 0.4 s sonar echo and a 25 kHz wave, before a cliff echo, a string fundamental and the kHz to Hz slip.
Quick answer 340 m/s, 50 Hz, 50 Hz with 0.02 s, no sound in a vacuum, 1 700 m, 300 m, 0.0136 m, 136 m, 3 m with 120 Hz, and kHz means times 1 000.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | 25 minutes |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: S5 Physics: Waves and Sound – Tutor Lesson Plan |
| Level | S5 |
02 Questions (10 items)
- FoundationA wave has a wavelength of 0.25 m and a frequency of 1 360 Hz. Find its speed.
- FoundationA wave has a period of 0.02 s. Find its frequency.
- FoundationA tuning fork vibrates 100 times in 2 s. Find its frequency and period.
- FoundationCan sound travel through a vacuum such as space? Why?
- IntermediateThunder is heard 5 s after the lightning flash (sound speed 340 m/s). How far away is the strike?
- IntermediateA sonar receives the seabed echo 0.4 s after sending (sound speed in water 1 500 m/s). Find the depth.
- IntermediateAn ultrasound has a frequency of 25 kHz and sound travels at 340 m/s in air. Find the wavelength.
- ChallengeA shout returns as an echo after 0.8 s (sound speed 340 m/s). How far away is the cliff?
- ChallengeA string 1.5 m long is fixed at both ends and carries waves at 360 m/s. Find the fundamental wavelength and frequency.
- Error redoA student puts 25 kHz into v = f lambda as 25 Hz and gets a wavelength of 13.6 m. What is wrong?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | 340 m/s (0.25 x 1 360) | Wave speed is frequency times wavelength, v = f lambda. |
| 2 | 50 Hz (1 / 0.02) | Frequency is the reciprocal of the period. |
| 3 | 50 Hz with a period of 0.02 s | Frequency is 100 over 2, and the period is its reciprocal. |
| 4 | No, sound is a mechanical wave and needs particles in a medium to pass the vibration on | Without particles there is nothing to vibrate, so a vacuum carries no sound. |
| 5 | 1 700 m (340 x 5) | Light arrives almost instantly, so the delay is the sound travel time. |
| 6 | 300 m (1 500 x 0.4 / 2) | The echo travels down and back, so half the path is the depth. |
| 7 | 0.0136 m, which is 13.6 mm | 25 kHz is 25 000 Hz, so lambda is 340 over 25 000. |
| 8 | 136 m (340 x 0.8 / 2) | An echo is a return trip, so one way is half of it. |
| 9 | A wavelength of 3 m giving 120 Hz | With both ends fixed the fundamental is half a wave, so the wavelength is twice the length. |
| 10 | kHz must be multiplied by 1 000, giving 0.0136 m | A factor of 1 000 in the unit makes the wavelength wrong by 1 000 times. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
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