S6 Chemistry: Instrumental Analysis (Paper 3: Challenge)
- 2026-11-12
S6 Chemistry: Instrumental Analysis (Paper 3: Challenge)
Ten items combining mass spectra, infrared and chemical tests to deduce structures, with dilution and percentage calculations.
Direct answers Answers in order: ethanoic acid, C2H4O2, 2.0e-4 mol dm-3, 2.5e-3 mol dm-3, bromoethane, an ethoxy group, they confirm each other, the two carbonyls of an anhydride, 1.0 percent, no.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S6 Chemistry: Instrumental Analysis |
| Level | S6 |
02 Questions (10 items)
- FoundationA compound has its molecular ion at m/z 60, a broad infrared band at 3300 and a strong band at 1710, and it releases gas with sodium hydrogencarbonate. What is it?
- FoundationElemental analysis gives 40.0 percent carbon, 6.7 percent hydrogen and 53.3 percent oxygen with relative molecular mass 60. What is the molecular formula?
- FoundationA solution has absorbance 0.48, molar absorption coefficient 1200 dm3 mol-1 cm-1 and path length 2.0 cm. What is its concentration?
- IntermediateA sample diluted 25 times reads 1.0e-4 mol dm-3 in the cell. What is the original concentration?
- IntermediateThe M peak is at m/z 109 and M+2 is of similar height. What is the compound?
- IntermediateA fragment at M minus 45 appears in the mass spectrum. Which group is most likely lost?
- ChallengeWhy check both retention time and the mass spectrum when identifying an unknown by GC-MS?
- ChallengeAn infrared spectrum shows two strong bands at 1800 and 1750 cm-1. Which group is most likely present?
- ChallengeA 0.500 g sample is made up to 250 cm3 and diluted fivefold before atomic absorption reads 4.0 ppm. What is the percentage by mass?
- Error redoMisconception drill: can infrared alone establish a molecular formula?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | Ethanoic acid | The gas from hydrogencarbonate proves a carboxylic acid group, and m/z 60 matches C2H4O2. |
| 2 | C2H4O2 | 60 times 0.40 over 12 gives two carbons, 60 times 0.067 gives four hydrogens and 60 times 0.533 over 16 gives two oxygens. |
| 3 | 2.0e-4 mol dm-3 | Divide 0.48 by the product of 1200 and 2.0. |
| 4 | 2.5e-3 mol dm-3 | Dilution divides the concentration, so recovering it multiplies by 25. |
| 5 | Bromoethane, C2H5Br | Bromine gives M and M+2 of similar height, and 24 plus 5 plus 80 gives 109. |
| 6 | An ethoxy group, OC2H5 | 45 is two carbons, five hydrogens and one oxygen, the mass of an ethoxy group. |
| 7 | The two confirm each other and avoid co-elution errors | An impurity with the same retention time can co-elute, while the mass spectrum gives a structural fingerprint, so only agreement is trustworthy. |
| 8 | The two carbonyls of an anhydride | An anhydride has two coupled carbonyls, so two strong bands appear close together. |
| 9 | 1.0 percent | 4.0 ppm times 5 gives 20 ppm in the made up solution, 0.25 L holds 5 mg, and 5 mg in 500 mg is 0.01. |
| 10 | No, mass spectrometry and elemental analysis are also needed | Infrared only shows functional groups; the formula needs the molecular ion mass together with the element ratios. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
In combined spectra questions, write the relative molecular mass first, then check each functional group against it.Tutor Registration →
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