S6 Chemistry Organic Chemistry (Functional Groups), Paper 2: oxidation, esterification and hydrolysis
- 2026-11-02
S6 Chemistry Organic Chemistry (Functional Groups), Paper 2: oxidation, esterification and hydrolysis
Paper 2 works through ethanol with sodium, ethanoic acid with carbonate, limiting reagents in esterification, dehydration to ethene, oxidation demand, the isomers of C3H6O2, ester hydrolysis with a mass balance and an alcohol combustion analysis.
Focus Write the balanced equation first, then take the mole ratio; esterification and hydrolysis both run one to one, so the limiting reagent is decided by moles rather than mass.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 25 |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: S6 Chemistry: Organic Chemistry (Functional Groups) |
| Level | Four basic, three advanced, two challenge and one error-repair item |
02 Questions (10 items)
- FoundationWhat is the molar mass of ethanol, C2H5OH, and how many moles are in 2.3 g?
- Foundation0.10 mol of ethanol reacts with excess sodium, two moles giving one mole of hydrogen. How many moles and grams of hydrogen form?
- Foundation0.10 mol of ethanoic acid reacts with excess sodium carbonate. What volume of carbon dioxide forms at 24 dm3 per mole?
- Foundation0.20 mol of ethanol and 0.15 mol of ethanoic acid are heated with concentrated sulphuric acid. Which is limiting, and what is the maximum mass of ethyl ethanoate?
- Intermediate0.10 mol of ethanol is dehydrated at 170 degrees Celsius. What amount, mass and volume of ethene results at 24 dm3 per mole?
- Intermediate0.10 mol of ethanol is oxidised completely to ethanoic acid. How many moles and grams of oxygen are needed?
- IntermediateThe formula C3H6O2 fits both a carboxylic acid and an ester. Give one example of each and state how many such isomers exist.
- Challenge8.8 g of ethyl ethanoate is hydrolysed completely. Find the moles and masses of ethanol and ethanoic acid formed.
- ChallengeBurning 0.10 mol of a saturated alcohol gives 0.20 mol of carbon dioxide and 0.30 mol of water. Find its formula, its name and the mass of 0.10 mol.
- Error redoError repair: a student claims that mixing ethanol and ethanoic acid simply makes ethyl ethanoate. What is wrong?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | 46.0 g per mole, so 0.05 mol | Two carbons give 24.0, six hydrogens 6.0 and one oxygen 16.0, so 46.0 g per mole, and 2.3 g is 0.05 mol. |
| 2 | 0.05 mol, which is 0.10 g | Two moles of ethanol release one mole of hydrogen, so half of 0.10 mol is 0.05 mol and its mass is 0.10 g. |
| 3 | 0.05 mol, which is 1.2 dm3 | Two moles of the acid release one mole of carbon dioxide, so 0.05 mol is produced and 0.05 times 24 is 1.2 dm3. |
| 4 | The acid is limiting, giving 0.15 mol or 13.2 g of ester | The alcohol and the acid react one to one and the acid runs out first, so 0.15 times 88.0 gives 13.2 g. |
| 5 | 0.10 mol, which is 2.8 g and 2.4 dm3 | Each mole of ethanol loses one water molecule and gives one mole of ethene, so 0.10 times 28.0 is 2.8 g and its volume is 2.4 dm3. |
| 6 | 0.10 mol, which is 3.2 g | The equation balances with one oxygen molecule per ethanol, so 0.10 mol of oxygen weighs 3.2 g. |
| 7 | Propanoic acid and methyl ethanoate, two isomers in all | A carboxylic acid needs one COOH group and the remaining two carbons give propanoic acid, while an ester needs one COO link and gives methyl ethanoate, so there are two. |
| 8 | 0.10 mol of each, so 4.6 g of ethanol and 6.0 g of acid | 8.8 over 88.0 is 0.10 mol and the hydrolysis is one to one, so the masses are 4.6 g and 6.0 g, which add to 10.6 g, the same as 8.8 g plus 1.8 g of water. |
| 9 | C2H6O, ethanol, with a mass of 4.6 g | Carbon is two and hydrogen is six, a saturated alcohol adds one oxygen, and 0.10 mol of the 46.0 molar mass weighs 4.6 g. |
| 10 | Wrong: esterification needs concentrated sulphuric acid and heat, and it is reversible so the yield stays below 100 per cent | Without a catalyst and heat the reaction is far too slow, and because it is reversible the water formed pushes the equilibrium back, so the yield never reaches 100 per cent. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
Book an S6 Chemistry tutorTutor Registration →
Questions and answers are written originally by the TutorZone team and are not taken from any school, publisher or examination authority paper. Every value is checked by computer.


