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S6 ICT | IT Project Management (Critical Path and Earned Value): Tutor Prep Guide (45-minute flow, script, common errors)

S6 ICT | IT Project Management (Critical Path and Earned Value): Tutor Prep Guide (45-minute flow, script, common errors)

  • 2026-11-15

Students can draw a Gantt chart, then ask how short the project can be and they start guessing at paths. This lesson turns a dependency table into two operations: the longest path sets the finish date, and the gap is float.

Objectives — By the end of the lesson students can: (1) draw the network from a dependency table and find the three paths of 7, 9 and 11 days, naming the longest as the critical path; (2) compute a float of 2 days for B and 4 days for C, and explain that a task with zero float delays the finish date; (3) compute a CPI of 0.84 and an SPI of 0.875 from BAC 120,000, PV 48,000, EV 42,000 and AC 50,000; (4) compute an EAC of about 142,857 from a CPI of 0.84 and state the overspend of 22,857.

01 Prerequisites (3-minute check)

If any of these fails, fix it before the lesson starts.

Skill Quick check Pass mark
Addition and comparison Three paths of 7, 9 and 11 days: which one sets the finish date The 11-day path
Percentages What is 35 per cent of a BAC of 120,000 42,000
Ratios EV of 42,000 divided by AC of 50,000 0.84
Reading a dependency table A takes 3 days and D waits for A, so when can D start Day 4

02 Lesson flow (45 minutes)

Time Stage Tutor does Student does
0-6 min Entry check Ask the three path lengths, 35 per cent, 42,000 over 50,000 and the start day; keep answers on the board Spoken answers, working on paper
6-14 min Act one: draw the network first Build arrows from the dependency table, write each duration on its arrow, add a start and an end node Students draw the same network
14-24 min Act two: the critical path is the longest one Paths A-C-E at 7 days, A-B-E at 9 and A-D-F at 11, so 11 days is the critical path Students name the tasks on the critical path
24-34 min Act three: float and earned value Float is critical length minus that path; BAC 120,000, PV 48,000, EV 42,000, AC 50,000 give CPI 0.84, SPI 0.875 and EAC 142,857 Students compute the floats and the CPI
34-42 min Question types with new numbers Six tasks and a new BAC, four phrasings of the same chain Students do one and write the unit
42-45 min Exit check Three spoken questions; note which act each error comes from All three correct

03 Teaching script (read it out)

Scene 1: Act one: table to network, and the network decides everything

A project question hands you a table: task code, duration, predecessors. Step one is always the network diagram, not a Gantt chart. Start from the start node: A has no predecessor, so one arrow leaves the start to A with 3 days on it. B, C and D all list A, so three arrows leave A. E waits for both B and C, so two arrows point into E. F waits only for D. Both E and F point into the end node. Once the diagram is right, every later question is just adding numbers along arrows.

E has two predecessors, so how many arrows point into E, and why?

Scene 2: Act two: the critical path is the longest path, not the shortest

Walk from start to end and add each path: A 3 plus C 2 plus E 2 is 7 days; A 3 plus B 4 plus E 2 is 9 days; A 3 plus D 5 plus F 3 is 11 days. The longest is 11, so the shortest possible project duration is 11 days, and that path is critical. Why the longest? Parallel work overlaps, but E waits for both B and C, so the people on the 9-day path finish and then wait for the 11-day path before the project closes. Tasks on the critical path have zero float: delay D by a day and the finish slips a day.

If D took 7 days instead of 5, would the critical path change, and what would the finish date become?

Scene 3: Act three: float is subtraction, earned value is two ratios

Float is the critical length minus the length of that path. The A-B-E crew needs 9 days against an 11-day critical path, so they have 2 days of slack, called float of 2 days; A-C-E at 7 days has a float of 4 days. Zero float means not one day of delay is allowed. Earned value asks for four numbers. PV is the value the plan says you should have delivered today, 40 per cent of 120,000, so 48,000. EV is the value actually delivered, 35 per cent, so 42,000. AC is the money actually spent, 50,000. CPI is EV over AC, 42,000 over 50,000, giving 0.84, below one meaning overspend. SPI is EV over PV, 42,000 over 48,000, giving 0.875, below one meaning behind schedule. EAC is BAC over CPI, 120,000 over 0.84, about 142,857, so at this rate the project overspends by 22,857.

What does a CPI of 0.84 say about the value delivered per dollar spent, and what does below one mean?

04 Question types and worked steps

Type Example Steps Answer
Find the critical path A 3, B 4 after A, C 2 after A, D 5 after A, E 2 after B and C, F 3 after D Draw the network, list every path, take the longest A-D-F at 11 days
Compute float Its path is 9 days and the critical path is 11 Critical length minus that path length 2 days for B and 4 days for C
Compute CPI and SPI BAC 120,000, PV 48,000, EV 42,000, AC 50,000 CPI is EV over AC, SPI is EV over PV CPI 0.84, SPI 0.875, both below one
Compute EAC CPI 0.84 with BAC 120,000 EAC is BAC over CPI, then subtract BAC About 142,857, an overspend of 22,857
Sanity check (teach this): Four checks: (1) the critical path total must equal the project duration, and any mismatch means a path was missed; (2) every task on the critical path must have zero float, and a non-zero float means the wrong path was chosen; (3) both CPI and SPI use EV as the numerator, so AC over EV is always wrong; (4) with a CPI below one the EAC must be at least BAC, and an EAC below BAC means the division is inverted.

05 Independent practice (3 questions)

Question Answer What to watch
A 3, B 4 after A, C 2 after A, D 5 after A, E 2 after B and C, F 3 after D: what is the shortest duration 11 days, on the path A-D-F Watch for students missing the 9-day A-B-E path
What is the float of task B 2 days, that is 11 minus 9 Check that the critical length is subtracted, not the task duration
BAC 120,000, PV 48,000, EV 42,000, AC 50,000: what is the CPI 0.84 42,000 over 50,000, and the numerator is EV

06 Common mistakes and what to say

Mistake Student writes Say this
Calling the shortest path critical Answering 7 days with A-C-E The critical path is the longest. The shortest path finishes early and waits, and the project still runs to the longest path.
Reversing the arrows Pointing the arrow from D to A An arrow means finishes before it starts. A precedes D, so the arrow runs A to D; reversing it makes every date wrong.
Inverting the CPI Dividing AC by EV to get 1.19 and calling it healthy EV is the value delivered and AC is the money spent, so 0.84 is right and below one means overspend.
Reading zero float as cannot start Delaying critical work to avoid a clash Zero float means no delay is allowed, not that work cannot begin. Critical tasks start at their earliest date and never slip.

07 Homework (paper, section and question numbers)

08 Exit check (last 5 minutes)

Question Answer Decision
A-D-F takes 11 days and A-B-E takes 9, so what is the shortest duration 11 days Wrong: reteach act two, the longest path sets the finish
BAC 120,000, EV 42,000, AC 50,000: the CPI 0.84, an overspend Wrong: reteach act three, EV is the numerator
CPI 0.84 with BAC 120,000: the EAC About 142,857 Wrong: reteach act three, EAC is BAC over CPI

09 Tutor FAQ

Which year level is this for?

Hong Kong S6 ICT asks students to find the critical path from a dependency table, explain float and judge project health from earned value figures. The S4 work on percentages and ratios is the prerequisite, so revise what one number divided by another means first.

Is 45 minutes enough?

Yes, provided act two gets ten minutes. The commonest error is calling the shortest path critical, so make students say out loud that the short path finishes early and waits.

Are these a real project figures?

No. 120,000, 50,000 and 35 per cent are teaching numbers for mental arithmetic. Real projects carry decimals, and the point is the relationship between the four figures and the direction of the judgement.

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