S6 Maths: The Binomial Theorem: Paper 4 (Error clinic)
Ten items on the usual slips: missing middle terms, confusing C(n, r) with permutations, and sign handling.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S6 Maths: The Binomial Theorem |
| Level | Error clinic |
| # | Answer | One-line note |
|---|---|---|
| 1 | 5 terms | The count is n + 1, so 4 + 1 = 5 terms. |
| 2 | 36 | C(9, 2) = (9 × 8) ÷ 2 = 36, not 72. |
| 3 | 10 | With r = 3, C(5, 3) = C(5, 2) = 10. |
| 4 | 12 | With r = 2, C(3, 2) × 2² = 3 × 4 = 12. |
| 5 | −3 | With r = 1, C(3, 1) x² (-1) = -3; the minus sign is easy to drop. |
| 6 | 1 | There is exactly one way to choose nothing, so C(n, 0) is always 1. |
| 7 | 6 | With r = 2, C(4, 2) × (-1)² = 6; an even power carries no minus sign. |
| 8 | 16 | The constant term is r = 0, giving C(4, 0) × 2^4 = 16. |
| 9 | 8 | With r = 3, C(4, 3) × 2 = 4 × 2 = 8. |
| 10 | The middle term 6x is missing; it is 9 + 6x + x² | The middle term is 2 × 3 × x = 6x, so squaring a binomial always gives three terms. |
Write the general term C(n, r) a^(n-r) b^r first, then put in r.Tutor Registration →
Questions and answers are written originally by the TutorZone team and are not taken from any school, publisher or examination authority paper. Every value is checked by computer.

