DSE Physics | Astronomy: parallax, luminosity and distance — lesson-prep guide for tutors
- 2026-11-02
Students can say the words light year, then multiply the wrong numbers when asked how far 20 parsecs is. This lesson separates the three distance tools and gives each one a formula that can be checked.
01 Prerequisites (3-minute check)
If any of these fails, fix it before the lesson starts.
| Skill | Quick check | Pass mark |
|---|---|---|
| Units | How many metres and light years is one parsec? | About 3.09 x 10^16 m, about 3.26 light years |
| Inverse square | If a source moves three times further away, what happens to flux? | It falls to one ninth, because flux goes as one over distance squared |
| Logarithms | What is log 100, and what is 10 squared? | 2, and 100: the same statement in two forms |
02 Lesson flow (60 minutes)
| Time | Stage | Tutor does | Student does |
|---|---|---|---|
| 0-5 min | Opening question | Write 4.2 light years for Proxima and 8 min 20 s for sunlight, ask why the units differ | Vote and name what each number measures |
| 5-15 min | Prerequisite check | Three quick items: parsec, inverse square, logarithms | Written answers, marked live |
| 15-37 min | Three-part script | Teach parallax, luminosity, then distance modulus and Hubble law | Recap the assumption of each tool in one sentence |
| 37-49 min | Question walk-through | Model four questions, writing units before substituting | Copy and recompute one themselves |
| 49-55 min | Independent practice | Circulate; ask only what the valid range of this formula is | Do three items and self-mark |
| 55-60 min | Exit check | Collect answers and count misses aloud | Written, no talking |
03 Teaching script (read it out)
Scene 1: Part 1: parallax and the parsec
If parallax falls from 0.05 to 0.02 arcseconds, does distance rise or fall, and by what factor?
Scene 2: Part 2: luminosity and the inverse square
Does luminosity change when a star is moved ten times further? What about flux?
Scene 3: Part 3: distance modulus and Hubble law
What must you already know before using the distance modulus, and before using Hubble law?
04 Question types and worked steps
| Type | Example | Steps | Answer |
|---|---|---|---|
| Parallax calculation | Given a parallax angle, find distance. | (1) Check the unit is arcseconds; (2) d = 1/p; (3) multiply by 3.26 for light years; (4) state the method limit. | Example: p = 0.05 arcsec gives 20 pc, about 65.3 ly. |
| Inverse-square comparison | Compare brightness of equal-luminosity stars. | (1) Write F proportional to L over d squared; (2) take the distance ratio; (3) square and invert; (4) convert to magnitudes if asked. | Example: 10 pc against 100 pc gives a flux ratio of 1 to 1/100. |
| Distance modulus | Given m and M, find d. | (1) Compute m – M; (2) divide by 5; (3) add 1 for the exponent; (4) d = 10^(1+(m-M)/5) pc. | Example: m = 6, M = 1 gives d = 100 pc. |
| Hubble law | Given redshift or speed, find distance. | (1) Get v from redshift when v is well below c; (2) d = v/H0; (3) align units in Mpc; (4) state the uniform-expansion assumption. | Example: v = 7000 km/s with H0 = 70 gives 100 Mpc. |
05 Independent practice (3 questions)
| Question | Answer | What to watch |
|---|---|---|
| A star has parallax 0.05 arcseconds. Give its distance in parsecs and light years. | 20 parsecs, and 20 times 3.26 is about 65.3 light years. | Check that the reciprocal comes first; doing 0.05 times 3.26 is the slip to catch. |
| Two equal-luminosity stars sit at 10 and 100 parsecs. Give the flux ratio. | 1 to 1/100, so the far star is 100 times fainter, a difference of 5 magnitudes. | Check for the square; a factor of 10 means the square was dropped. |
| A star has m = 6 and M = 1. Find its distance. | m – M = 5, log(d/10) = 1, so d = 100 parsecs. | Check that 5 divided by 5 is then added to 1; answering 10 pc is the common error. |
06 Common mistakes and what to say
| Mistake | Student writes | Say this |
|---|---|---|
| Treating parallax as proportional to distance | Writes that a larger parallax means a greater distance. | It is inverse. A parallax of 0.05 is 20 parsecs and 0.02 is 50. Smaller denominator, larger answer. |
| Confusing luminosity with flux | Writes that the star gets dimmer, so its luminosity falls. | Luminosity is what the star emits. What changes is flux, because the same energy spreads over a larger sphere. |
| Dropping the plus one | Gets m – M = 5 and writes d = 10 parsecs. | Five over five is one, but you still add the original 10, so it is 10 squared. Writing 10 loses a power of ten. |
| Mixing units in Hubble law | Divides km/s by a distance in parsecs. | H0 is km/s per megaparsec, so the distance must be in Mpc. Otherwise the answer is wrong by a factor of a million. |
07 Homework (paper, section and question numbers)
- Secondary Physics index: finish the three items, then pair logarithms with the radioactive decay chapter — Exercises 1-3 on this page
08 Exit check (last 5 minutes)
| Question | Answer | Decision |
|---|---|---|
| What distance corresponds to a parallax of 0.1 arcseconds? | 10 parsecs | Cannot answer: reteach part 1 |
| A star of equal luminosity moves four times further. What happens to flux? | It falls to one sixteenth | Cannot answer: reteach part 2 |
| State the distance modulus formula. | m – M = 5 log(d/10), with d in parsecs | Cannot answer: reteach part 3 |
09 Tutor FAQ
Which year is this for?
S6 elective astronomy mainly; S5 classes that have finished waves and optics can start it earlier.
Must students memorise the Hubble constant?
The paper supplies it. What they must know is the unit, km/s per megaparsec, because the unit decides the distance unit.
Is there a matching paper?
The homework link goes to the secondary Physics index, which pairs with the radioactive decay chapter on exponentials.
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A TutorZone lesson-prep guide. Written by the TutorZone team; questions and lesson flow are original and are not taken from any school or publisher material.


