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DSE Physics: Nuclear Energy — Tutor Lesson Plan (fission, fusion, E = mc²)

DSE Physics: Nuclear Energy — Tutor Lesson Plan (fission, fusion, E = mc²)

  • 2026-11-01

Students can recite E = mc² but answer where the energy comes from with it comes out of the atom. The real source is the small mass that disappears.

Objectives — The student can describe a fission chain reaction and the job of control rods, calculate energy released from a mass defect, and compare fusion with fission including the three rules of radiation protection.

01 Prerequisites (3-minute check)

If any of these fails, fix it before the lesson starts.

Skill Quick check Pass mark
Atomic structure Protons, neutrons, electrons Mass sits in the nucleus
Conservation of energy Energy changes form Kinetic and internal energy
Units MeV and joules 1 MeV = 1.6 x 10^-13 J

02 Lesson flow (60 minutes)

Time Stage Tutor does Student does
0-8 min Prerequisite check What is inside a nucleus Names the nucleus
8-22 min Fission U-235 absorbs a slow neutron Draws one generation
22-38 min Mass defect Delta m into energy 3.20e-11 J
38-50 min Fusion Light nuclei join, very hot Two similarities and differences
50-56 min Reactor and protection Rods, shielding, distance, time Matches three rules
56-60 min Exit check Three questions marked Works alone

03 Teaching script (read it out)

Scene 1: Fission runs on neutrons, and it chains

A U-235 nucleus absorbing a slow neutron splits into two fragments and releases two or three neutrons.
Those neutrons trigger further splits: that is a chain reaction, and it sustains itself while more than one neutron per split goes on to cause another.
Control rods (boron, cadmium) absorb spare neutrons; the moderator (water, graphite) slows fast neutrons down. Keep the two jobs apart.

Student answers what happens to the rate when a control rod is withdrawn (it rises).

Scene 2: The energy comes from the missing mass

Masses before and after the reaction are not equal, and the difference is what becomes energy: E = mc squared.
One U-235 fission releases about 200 MeV, a mass defect of roughly 0.215 u (about 3.56e-28 kg), which is 3.20e-11 J.
Burning coal gives about 2.9 x 10^7 J per kilogram, so the same energy needs only about 0.0 kg of uranium fuel: several orders of magnitude apart.

Student computes the energy for a mass defect of 0.2 u (0.2 x 931.5 = about 186 MeV).

Scene 3: Fusion is harder but denser

Deuterium and tritium fuse into helium plus a neutron, and the nuclei need very high temperature to overcome electrostatic repulsion.
The Sun runs on fusion; fusion waste is shorter lived, but ignition is very hard to engineer.
Radiation protection: less time, more distance, thicker shielding such as concrete or lead.

Correct this: fusion is not waste free, its waste simply has a much shorter half-life.

04 Question types and worked steps

Type Example Steps Answer
Fission equation U-235 + n gives Ba-141 + Kr-92 + 3n Conserve mass number and atomic number Three neutrons
Energy Delta m = 0.2 u E = mc squared, or x 931.5 MeV per u About 186 MeV
Half-life Waste after four half-lives Halve each time 6.2% left
Comparison Fusion against fission Fuel, conditions, waste One point each
Sanity check (teach this): Mass numbers must balance on both sides of the equation, and so must atomic numbers. If energy is wanted in MeV while mass is in kilograms, convert first, otherwise the answer is out by 10^13.

05 Independent practice (3 questions)

Question Answer What to watch
Convert 200 MeV to joules 3.20e-11 J 200 x 10^6 x 1.6 x 10^-19
Percentage left after four half-lives 6.2% Halve four times
Why reactors use slow neutrons They are absorbed by U-235 far more easily The moderator slows them

06 Common mistakes and what to say

Mistake Student writes Say this
Control rods called a moderator says rods slow neutrons down Rods absorb neutrons; the moderator slows them.
Missing c squared uses E = delta m Without c squared the answer is 10^17 times too small.
Fusion called waste free claims zero radioactivity Fusion waste is short lived, not absent.
Half-life treated as linear zero left after four half-lives Each half-life halves the amount; it never reaches zero.

07 Homework (paper, section and question numbers)

08 Exit check (last 5 minutes)

Question Answer Decision
200 MeV in joules 3.20e-11 J All right: move to radiation and society
Job of a control rod Absorbs spare neutrons One wrong: re-teach the reactor
Percentage after four half-lives 6.2% Two wrong: repeat scene 2

09 Tutor FAQ

Memorise 931.5 MeV per u?

The paper usually gives the conversion; knowing the size and the method matters more.

Which releases more, fission or fusion?

Per kilogram fusion does, but every commercial reactor today is fission.

Is all radiation harmful?

Dose decides risk, and background radiation exists; the three rules cut the dose.

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