S5 Biology: Nervous System and Coordination prep guide | Action potentials, synaptic delay and reflex timing
- 2026-11-01
Students can draw a neurone, then answer “how is a strong signal shown” with “a bigger action potential”. The key idea of this lesson is that action potentials are fixed in size and strength is coded as frequency.
01 Prerequisites (3-minute check)
If any of these fails, fix it before the lesson starts.
| Skill | Quick check | Pass mark |
|---|---|---|
| Membrane structure | Which part of a phospholipid is hydrophilic | The head |
| Active transport | Ions moved per cycle of the sodium-potassium pump | 3 Na+ out, 2 K+ in |
| Stimulus and response | Definition of a reflex | A fast response not involving conscious thought |
02 Lesson flow (60 minutes)
| Time | Stage | Tutor does | Student does |
|---|---|---|---|
| 0-12 min | Neurone structure and resting potential | Inside about 70 mV below outside | Negative inside |
| 12-26 min | The full action potential | -70 to -55 to +30 mV | Fixed 100 mV amplitude |
| 26-38 min | Synaptic transmission | 20 nm cleft, transmitter diffuses | 0.5 ms delay each |
| 38-48 min | Reflex arc timing | 1.2 m path, two synapses | About 13 ms in total |
| 48-56 min | Refractory period and frequency coding | Refractory period 2 ms | Up to 500 impulses per second |
| 56-60 min | Exit check | Three questions collected | Done independently |
03 Teaching script (read it out)
Scene 1: Resting and action potentials: ion traffic sets the voltage
A stimulus lifting the membrane potential to the threshold of -55 mV, 15 mV above rest, opens voltage-gated sodium channels. Na+ floods in and depolarises the membrane to about +30 mV; potassium channels then open, K+ leaves, the membrane repolarises and briefly overshoots before the pump restores the resting state.
The amplitude is +30 minus -70, which is 100 mV, and it is all-or-nothing. Once threshold is crossed every impulse is the same size, so stimulus strength cannot be encoded in height.
Strength is coded as frequency instead: with a 2 ms refractory period the theoretical maximum is 1000 / 2, which is 500 impulses per second.
Task: mark threshold and peak on a potential graph and work out how many mV the depolarisation spans (15 mV).
Scene 2: The synapse: one-way, delayed and able to amplify
One-way traffic is guaranteed because vesicles sit only in the presynaptic knob and receptors only on the postsynaptic membrane, which is why a reflex arc never runs backwards.
Each synapse adds about 0.5 ms of delay, so the number of synapses in an arc directly sets the response time. The delay is not a defect: it lets signals summate and gives drugs a target.
Excitatory transmitters depolarise and inhibitory ones hyperpolarise the membrane, and the same transmitter can do either depending on the receptor. The transmitter does not decide the effect; the receptor does.
Task: explain one-way transmission with “vesicles in front, receptors behind” and give one example of an inhibitory transmitter.
Scene 3: Reflex timing and the refractory period: numbers make it real
With two synapses at 0.5 ms each, the total comes to about 13.0 ms, plus the mechanical time for the muscle to contract.
The same path along unmyelinated fibres at 0.5 m/s would need 2,400 ms, which is 200 times slower. That is the value of myelin and saltatory conduction at the nodes of Ranvier, and why multiple sclerosis slows reactions.
The 2 ms refractory period does two jobs: it caps the firing rate at 500 impulses per second and it keeps each action potential travelling one way instead of bouncing back and forth.
Task: with three synapses and a 1.5 m path, find the total conduction plus synaptic time (15 ms + 1.5 ms = 16.5 ms).
04 Question types and worked steps
| Type | Example | Steps | Answer |
|---|---|---|---|
| Labelling | Potential graph | Mark resting, threshold, peak, repolarisation | Amplitude 100 mV |
| Comparison | Myelinated versus bare axons | Saltatory conduction skips membrane segments | 200 times faster |
| Calculation | Response time | Distance / speed, plus synaptic delays | 13.0 ms |
| Explanation | Frequency coding | All-or-nothing amplitude, strength in frequency | Up to 500 per second |
Direction check: sodium entering means depolarisation, potassium leaving means repolarisation, and the pair cannot be swapped; a rising membrane potential is always Na+ influx.
Magnitude check: 13 ms is milliseconds, far faster than a blink at 100 to 400 ms; a 13 second answer is a unit error. The 500 per second figure is a theoretical ceiling, since real firing rates are much lower.
05 Independent practice (3 questions)
| Question | Answer | What to watch |
|---|---|---|
| Amplitude between rest and peak | 100 mV | +30 minus -70 |
| Maximum firing rate with a 2 ms refractory period | 500 per second | 1000 / 2 |
| Conduction time over 1.2 m at 100 m/s | 12.0 ms | 1.2 / 100 x 1000 |
| How much faster is a myelinated axon | 200 times | 100 / 0.5 |
06 Common mistakes and what to say
| Mistake | Student writes | Say this |
|---|---|---|
| Thinking a stronger stimulus gives a bigger impulse | Amplitude scaling with stimulus | An action potential is all-or-nothing. A louder signal is not taller, just more frequent. |
| Swapping the Na+ and K+ movements | Calling repolarisation a sodium influx | Sodium in means depolarisation, potassium out means repolarisation. Swap them and the whole answer falls. |
| Forgetting the synaptic delay | Timing the conduction only | Every synapse adds about half a millisecond, so count the synapses in the arc. |
| Treating a reflex as conscious | Saying the brain decides a reflex | A reflex arc bypasses the brain, which is why it is fast. The brain can later modify it, but it is not the starting point. |
07 Homework (paper, section and question numbers)
- Secondary Biology chapter index — All chapters
- Biology practice paper — Nervous coordination questions 7 to 13
08 Exit check (last 5 minutes)
| Question | Answer | Decision |
|---|---|---|
| Amplitude of the action potential | 100 mV | Correct means hormonal coordination comes next |
| Why synapses are one-way | Vesicles in front, receptors behind | Wrong means redo synapses |
| Two jobs of the refractory period | Limits frequency, keeps direction | Two errors means restart the first act |
09 Tutor FAQ
Why is the action potential all-or-nothing?
Once threshold is crossed the sodium channels open in a positive feedback loop, so the impulse runs to completion regardless of the original stimulus size.
How does myelin speed conduction?
Myelin insulates the axon so ions exchange only at the nodes of Ranvier, letting the signal jump forward and cutting the time spent recharging the membrane.
How does nervous coordination differ from hormonal?
Nervous signals travel fast, act briefly and follow fixed routes, while hormones travel in blood, act slowly but persist and reach many targets.
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A TutorZone lesson-prep guide. Written by the TutorZone team; questions and lesson flow are original and are not taken from any school or publisher material.


