IGCSE 数学 0580 Paper 2(Extended)模拟卷|70 分・1 小时 30 分・可用计算机
- 2026-10-30
练习卷 · IGCSE 数学 0580 Paper 2(Extended)
IGCSE 数学 0580 Paper 2(Extended)模拟卷:20 题共 70 分、1 小时 30 分、可用计算机,涵盖数字与代数、图形与空间、数据与概率三大范畴,每题附答案与完整计算步骤,题目版与答案版 PDF 可即时下载,方便家长即时对答案。全部题目原创,非历届试题。
卷面资料 年级:IGCSE(Extended) | 科目:数学 | 时限:90 分钟 | 总分:70 分 | 题数:20
甲部 数字与代数(28 分)
全部题目必须作答,须展示计算步骤。
| # | 题目 | 答案与评分要点 |
|---|---|---|
| 1 | Expand and simplify 5(2x − 3) − 2(x − 4). | 10x − 15 − 2x + 8 = 8x − 7 |
| 2 | Solve 3x + 7 = 4x − 5. | 3x + 7 = 4x − 5 gives x = 12; check 3 × 12 + 7 = 43 = 4 × 12 − 5 |
| 3 | In a sale a jacket is reduced by 15 per cent and now costs $680. Work out the original price. | 680 ÷ 0.85 = $800 |
| 4 | Expand and simplify (x + 6)(x − 4). | x² + 2x − 24 |
| 5 | Factorise completely 6x² + 15x. | 3x(2x + 5) |
| 6 | y is directly proportional to x². When x = 7, y = 98. Find y when x = 11. | k = 98 ÷ 49 = 2, so y = 2 × 121 = 242 |
| 7 | Work out (4.2 × 10⁵) × (3.5 × 10⁻³), giving your answer in standard form. | 14.7 × 10² = 1.47 × 10³ |
| 8 | $4,500 is invested at 3.2 per cent per year compound interest. Find the value after 3 years, to the nearest cent. | 4500 × 1.032³ = $4,945.97 |
| 9 | Simplify (x² − 9) ÷ (x² + x − 12). | (x − 3)(x + 3) ÷ (x − 3)(x + 4) = (x + 3)/(x + 4) for x ≠ 3 |
乙部 图形与空间(23 分)
如无特别说明,答案须附单位。
| # | 题目 | 答案与评分要点 |
|---|---|---|
| 10 | A right-angled triangle has legs 9 cm and 12 cm. Work out the length of the hypotenuse and the area of the triangle. | hypotenuse = √(81 + 144) = 15 cm; area = ½ × 9 × 12 = 54 cm² |
| 11 | A sector of a circle of radius 7 cm has angle 120°. Using π = 3.142, work out the arc length. | 120/360 × 2 × 3.142 × 7 = 14.66 cm |
| 12 | A cone has base radius 6 cm and height 10 cm. Using π = 3.142, work out its volume. | ⅓ × 3.142 × 36 × 10 = 377.04 cm³ |
| 13 | Two triangles are similar. The area of the smaller is 50 cm² and the ratio of corresponding lengths is 5 : 7. Find the area of the larger triangle. | 50 × 49 ÷ 25 = 98 cm² |
| 14 | A ladder 6.5 m long leans against a vertical wall with its foot 2.5 m from the wall. Work out the height reached and the angle the ladder makes with the ground. | height = √(42.25 − 6.25) = 6.0 m; angle = cos⁻¹(2.5 ÷ 6.5) = 67.4° |
| 15 | Work out the interior angle of a regular 12-sided polygon. | (12 − 2) × 180 ÷ 12 = 150° |
丙部 数据与概率(19 分)
概率可用分数或小数作答。
| # | 题目 | 答案与评分要点 |
|---|---|---|
| 16 | Five test scores are 12, 15, 9, 18 and 21. Work out the mean score. | total 75 ÷ 5 = 15 |
| 17 | The ages of 10 club members are 3, 5, 7, 8, 8, 10, 12, 14, 15 and 18. Work out the median age. | median = (8 + 10) ÷ 2 = 9 |
| 18 | A bag holds 5 red, 3 blue and 2 green counters. One counter is taken at random. (a) Work out the probability that it is not red. (b) Two counters are then taken without replacement; work out the probability that both are red. | (a) 5 of the 10 counters are not red, so 1/2. (b) 5/10 × 4/9 = 2/9 ≈ 0.222 |
| 19 | A scatter graph of 20 students plots height against shoe size, with the points rising from left to right. Describe the correlation and say what it means. | Positive correlation: taller students tend to have larger shoe sizes |
| 20 | The probability that a component is faulty is 0.04. In a batch of 500 components, work out the expected number of faulty components. | 500 × 0.04 = 20 |
TutorZone 练习卷|题目与文章为原创,并非任何学校或出版社的教材。
想教书?TutorZone 正在招募导师 —— 免费登记,招生与配对交给平台。 了解详情 →


