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IB Maths AA: Introductory Calculus — Tutor Lesson Plan (derivatives, tangents, stationary points)

IB Maths AA: Introductory Calculus — Tutor Lesson Plan (derivatives, tangents, stationary points)

  • 2026-10-28

The first question in an IB calculus problem is not how to differentiate but whether the question wants a slope or an extreme value. One cubic separates the two.

Objectives — the student can apply the power rule and explain it as an instantaneous rate, write the tangent at a point, and locate stationary points and classify them.

01 Prerequisites (3-minute check)

If any of these fails, fix it before the lesson starts.

Skill Quick check Pass mark
Power rule For f of x = x cubed – 3x + 2, what is f dash of x? 3x squared – 3
Substitution What is f of 2? 4
Line equation Slope 9 through (2, 4) y = 9x – 14

02 Lesson flow (60 minutes)

Time Stage Tutor does Student does
0-10 min Slope to derivative From secant gradient to tangent gradient State the difference
10-24 min Power rule x cubed – 3x + 2 becomes 3x squared – 3 Differentiate term by term
24-36 min Tangent line m equals f dash of 2, point (2, f of 2) Write y = 9x – 14
36-48 min Stationary points f dash equals zero gives x = plus or minus 1 Classify each
48-56 min IB answer format Method and reason, not answer alone Rewrite one answer
56-60 min Exit check Three questions marked Finish alone

03 Teaching script (read it out)

Scene 1: From secant to tangent: what a derivative is

The secant gradient is f of x plus h minus f of x, all over h. As h shrinks the secant approaches the tangent, and the limit is f dash of x.
For x cubed – 3x plus 2 the power rule gives 3x squared – 3, a different slope at every point.

Student explains why f dash still contains x.

Scene 2: The tangent line: slope first, point second

At x = 2 the gradient is f dash of 2, that is 3 times 4 minus 3, so 9, and the point is f of 2, that is 8 minus 6 plus 2, so 4.
Point-slope form gives y minus 4 equals 9 times x minus 2, so y = 9x – 14, and the -14 is computed, not recalled.

Student calculates the y-intercept of the tangent (-14).

Scene 3: Stationary points: zero derivative is only a candidate

3x squared – 3 = 0 gives x = 1 or -1. At x = 1 the value is 0, a minimum; at x = -1 it is 4, a maximum.
Test the sign: at x = 0 the derivative is -3, so the curve falls there, which makes -1 a maximum and 1 a minimum.

Note: IB says justify, so the sign test must be written down.

04 Question types and worked steps

Type Example Steps Answer
Differentiate f of x = x cubed – 3x + 2 Multiply by the index, drop it by one f dash = 3x squared – 3
Tangent at x = 2 m equals f dash of 2, point (2, f of 2) y = 9x – 14
Stationary points f dash equals zero Solve then test the sign x = 1 minimum 0, x = -1 maximum 4
Rate of change distance function to speed Differentiate position State the units
Sanity check (teach this): The tangent meets the curve at the point of contact, so substituting x = 2 into y = 9x – 14 must return f of 2, which is 4.

05 Independent practice (3 questions)

Question Answer What to watch
Differentiate x cubed – 3x + 2 3x squared – 3 Constant term becomes zero
Gradient of the tangent at x = 2 9 Differentiate before substituting
The two stationary points (1, 0) and (-1, 4) Say which is the maximum

06 Common mistakes and what to say

Mistake Student writes Say this
Keeping the constant f dash written 3x squared – 3 + 2 A constant has no slope, so it differentiates to zero.
Using f of x as the gradient m written 4 The gradient always comes from f dash, not f.
Stopping at the stationary point only x = plus or minus 1 IB wants the sign test, which is the justify mark.
Losing the units speed written as distance Differentiating changes the unit; speed is metres per second.

07 Homework (paper, section and question numbers)

08 Exit check (last 5 minutes)

Question Answer Decision
Value of f of 2 4 All three right: move to integration
Tangent at x = 2 y = 9x – 14 One wrong: re-teach point-slope form
Both stationary points and their nature (1, 0) minimum, (-1, 4) maximum Two wrong: repeat scene 2

09 Tutor FAQ

Does IB examine the limit definition?

Paper 1 rarely asks for the derivation, but Paper 3 and exploration work can ask what the limit means, so scene 1 stays.

Can a calculator differentiate?

It can check an answer, but the marks are for the working, not the output.

How does this chapter relate to functions?

The functions chapter reads shape, calculus reads slope and extremes, and one cubic links both.

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A TutorZone lesson-prep guide. Written by the TutorZone team; questions and lesson flow are original and are not taken from any school or publisher material.