IB Mathematics: Probability and Expectation (Foundation, 10 Questions)
Ten foundation items on classical probability: equally likely outcomes, complementary events, the two-dice sample space and expected counts. Each answer starts from favourable over total outcomes and is reduced to lowest terms, with a note.
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | about 25 minutes |
| Difficulty mix | Foundation 10 |
| Chapter | Chapter: IB Mathematics: Probability and Expectation |
| Level | IB |
| # | Answer | One-line note |
|---|---|---|
| 1 | 1/2 | Three of the six outcomes (2, 4 and 6) are even, so 3/6 simplifies to 1/2. |
| 2 | 2/5 | There are 4 favourable outcomes out of 10, and 4/10 simplifies to 2/5. |
| 3 | 1/4 | There are 13 hearts in the pack, and 13/52 simplifies to 1/4. |
| 4 | 1/2 | Two of the four equally likely outcomes (HH and TT) are the same, so 2/4 = 1/2. |
| 5 | 1/3 | Only 5 and 6 qualify, so the probability is 2/6 = 1/3. |
| 6 | 0.65 | The complement is 1 minus the original probability: 1 – 0.35 = 0.65. |
| 7 | 1/6 | Six of the 36 ordered outcomes total 7, and 6/36 simplifies to 1/6. |
| 8 | 2/5 | Only A and E are vowels, so the probability is 2 out of 5. |
| 9 | 0.93 | The 93 sound items give 93/100 = 0.93. |
| 10 | 10 times | The expected count is the number of trials times the probability: 60 x 1/6 = 10. |
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