IB Mathematics: Probability and Expectation (Challenge, 10 Questions)
- 2026-11-06
IB Mathematics: Probability and Expectation (Challenge, 10 Questions)
Ten challenge items on sampling without replacement, geometric probability, expected net gain, the standard deviation of a binomial, E(X squared) and the birthday problem, each needing full reasoning with complements or the variance identity.
Quick answer Answers in order: 5/14, 5/8, 23/28, 0.2826, -$4, E = 6 with SD about 2.05, 0.6, 329/6 or about 54.83, 17/72 or about 0.236, option B by $4.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | about 45 minutes |
| Difficulty mix | Challenge 10 |
| Chapter | Chapter: IB Mathematics: Probability and Expectation |
| Level | IB |
02 Questions (10 items)
- ChallengeA bag holds 5 red and 3 white balls. Two are drawn without replacement. Find the probability that both are red.
- ChallengeFrom the same bag of 5 red and 3 white balls, two are drawn without replacement. Find the probability that the second ball is red.
- ChallengeFrom the same bag, three balls are drawn without replacement. Find the probability that at least one is white.
- ChallengeA point is chosen at random inside a square of side 10 cm. Find the probability that it lies inside a circle of radius 3 cm (take pi = 3.14).
- ChallengeA raffle costs $8 per ticket, wins $200 with probability 1/50. Find the expected net gain per ticket.
- ChallengeX is binomial with n = 20 and p = 0.3. Find E(X) and the standard deviation to 2 decimal places.
- ChallengeA and B are independent with P(A) = 0.5 and P(A union B) = 0.8. Find P(B).
- ChallengeX is the total of two fair dice. Find E(X squared).
- ChallengeThree people are chosen at random. Find the probability that at least two share a birth month, assuming 12 equally likely months.
- ChallengeOption A pays $20 for certain; option B pays $80 with probability 0.3 and nothing otherwise. Which has the higher expectation, and by how much?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | 5/14 | (5/8) x (4/7) = 20/56 = 5/14; the denominator drops by one after the first draw. |
| 2 | 5/8 | By symmetry the second draw has the same marginal probability as the first, namely 5/8, with no case split needed. |
| 3 | 23/28 | All red is (5/8)(4/7)(3/6) = 5/28, so the answer is 1 – 5/28 = 23/28. |
| 4 | 0.2826 | The circle has area 9 x 3.14 = 28.26, which over the square area of 100 gives 0.2826. |
| 5 | -$4 | The expected prize is 200/50 = $4, and 4 – 8 = -4 dollars. |
| 6 | E(X) = 6, SD is about 2.05 | E = np = 6 and Var = np(1 – p) = 4.2, so the standard deviation is the square root of 4.2, about 2.05. |
| 7 | 0.6 | Independence gives 0.5 + q – 0.5q = 0.8, so 0.5q = 0.3 and q = 0.6. |
| 8 | 329/6, about 54.83 | The variance is 2 x 35/12 = 35/6, so E(X squared) = 35/6 + 49 = 329/6. |
| 9 | 17/72, about 0.236 | All different is (12 x 11 x 10)/1728 = 1320/1728, so the answer is 1 – 1320/1728 = 17/72. |
| 10 | Option B, by $4 | Option B has expectation 0.3 x 80 = $24, which is $4 above option A. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
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