P1 Maths: Addition within 20 (10 Challenge Items)
Ten challenge items: comparing 9+7 with 8+6, working back to a missing addend, three single digits making 20, 5+5+5+5, deciding whether a sum passes 20, rows of seats and comparing totals.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 25 |
| Difficulty mix | Foundation 2 · Intermediate 3 · Challenge 3 · Error redo 2 |
| Chapter | Chapter: P1 Maths: Addition within 20 |
| Level | P1 Maths |
| # | Answer | One-line note |
|---|---|---|
| 1 | 16 and 14 | 9 plus 1 makes 10 then add 6 for 16; 8 plus 2 makes 10 then add 4 for 14. |
| 2 | 9 | 18 take away 9 is 9, so the two numbers are equal. |
| 3 | 19 and 20 | 15 plus 4 is 19, and 19 plus 1 makes exactly 20. |
| 4 | 9 + 8 + 3 = 20, and other sets also work, for example 9 + 7 + 4. | Make ten first, then use the other two digits to make another ten. |
| 5 | 20 | Four fives add up to 20, which is four times five. |
| 6 | 7 + 7 + 7 = 21, which is greater than 20; 6 + 6 + 6 = 18, which is not. | Work out each sum first, then compare it with 20. |
| 7 | 6 | 20 take away 14 is 6, and 14 plus 6 makes exactly 20. |
| 8 | 18 seats | 9 plus 9 is 18; equal rows are quickest with the doubles fact. |
| 9 | There are 15 beads in total, which is 3 more than 12. | Work out 6 plus 9 first, then compare the total with 12. |
| 10 | 3 plus 9 is 12, not 11. | After making ten from the 9, the remaining 2 must still be added. |
Book a primary maths tutorTutor Registration →
Questions and answers are written originally by the TutorZone team and are not taken from any school, publisher or examination authority paper. Every value is checked by computer.

