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Primary 1 Maths | Addition within 20 Lesson-Prep Guide (for tutors) | Make-ten, number line, commutativity

Primary 1 Maths | Addition within 20 Lesson-Prep Guide (for tutors) | Make-ten, number line, commutativity

  • 2026-11-08

A pupil can get 8 + 5 = 13 by counting fingers, but that method fails in Primary 2. This lesson replaces counting with splitting: 8 needs 2 to reach 10, so take 2 out of the 5.

Objectives — The pupil can: (1) use make-ten for carrying addition within 20 (8 + 5 = 8 + 2 + 3 = 13); (2) start from the larger addend on a number line and jump forward; (3) explain commutativity (3 + 5 is the same as 5 + 3); (4) solve 9 + 7 without fingers.

01 Prerequisites (3-minute check)

If any of these fails, fix it before the lesson starts.

Skill Quick check Pass mark
Number bonds to 10 knows which pairs make 10 1+9 up to 5+5
Number line can count forward on a line from 8 to 13

02 Lesson flow (40 minutes)

Time Stage Tutor does Student does
0–5 min Diagnose ask how many 8 needs to reach 10 answers 2
5–15 min Make-ten 8 + 5: split 5 into 2 + 3 writes 8 + 2 + 3 = 13
15–25 min Number line start at 8, jump 5 lands on 13
25–33 min Commutativity 3 + 5 against 5 + 3 same answer, with a reason
33–40 min Exit check three questions no fingers

03 Teaching script (read it out)

Scene 1: Act 1: Make-ten by splitting the second number

Take 8 + 5. Do not count from 8 to 13. Ask how many 8 needs to reach 10: two. Take 2 out of the 5, leaving 3. Then 8 + 2 = 10, and 10 + 3 = 13. Write it as one line: 8 + 5 = 8 + 2 + 3 = 13. The point is that 10 is the friendly number, because adding to 10 only changes the tens digit.

Tutor line: “How many does 8 need to reach 10? Take 2 from the 5. How many are left in the 5?”

Scene 2: Act 2: Start from the larger number on the line

Check the same question on a number line: start at 8, jump 5 forward, land on 13. Emphasise starting from the larger addend, because there are fewer jumps and fewer chances to slip. For 3 + 9, start at 9 and jump 3, not start at 3 and jump 9.

Tutor line: “Put your finger on 8. Jump 5 forward. One, two, three, four, five. Where are you?”

Scene 3: Act 3: Commutativity is seen, not memorised

Lay out 3 red and 5 blue counters and ask how many altogether. Then swap the two piles and ask again. The total is unchanged. Only now state that 3 + 5 is the same as 5 + 3, and connect it back to Act 2: this is why any addition can start from the larger number.

Tutor line: “You swapped them. Did the total change? So what about 3 + 5 and 5 + 3?”

04 Question types and worked steps

Type Example Steps Answer
Carrying addition: 8 + 5 find what the second number needs to reach ten, split, add ten, add the rest past ten you just write the digit
Number line: from 8 jump 5 set the start, jump forward, read the landing point start from the larger number
Commutativity: 3 + 5 = ? + 3 identify the known addend, use the rule to fill the blank the two addends swap
Word problem: Ben has 9 sweets and buys 7 more find both numbers, make ten, give the unit the answer needs “sweets”
Sanity check (teach this): Keep the sum at or below 20; do not use 15 + 8 = 23 in this lesson. Always split the second addend, never the first, or the steps blur. On the number line, start from the larger addend, not from the first number written.

05 Independent practice (3 questions)

Question Answer What to watch
8 + 5 = ? 13 8 + 2 + 3
9 + 7 = ? 16 9 + 1 + 6
7 + 4 = ? 11 7 + 3 + 1
On a number line, jump 8 forward from 6 14 or jump 6 from 8
4 + 9 = 9 + ? 4 commutativity

06 Common mistakes and what to say

Mistake Student writes Say this
Counting from one on fingers counting 8 + 5 from 1 “Do not start at 1. 8 needs 2 to reach 10, so take 2 from the 5.”
Splitting the wrong addend splitting 8 into 5 + 3 “Split the second number, not the first.”
Jumping from the first number 3 + 9: jumping 9 from 3 “Start at 9 and jump 3.”
Missing the unit answering 13 with no unit “Thirteen what? Say thirteen sweets.”

07 Homework (paper, section and question numbers)

08 Exit check (last 5 minutes)

Question Answer Decision
7 + 6 = ? 13 if wrong: reteach splitting 6 into 3 + 3
9 + 8 = ? 17 if wrong: reteach that 9 needs 1
5 + 7 = 7 + ? 5 if wrong: reteach commutativity

09 Tutor FAQ

The pupil gets the right answer with fingers. Why stop it?

Fingers work up to 20 and then fail completely at fractions and three-digit numbers in Primary 2. Make-ten extends; replacing it later is harder than building it now.

Must the second addend always be the one split?

Yes. Fixing one step gives the pupil a single stable procedure. Allowing either split creates confusion about which number to break.

Should number bonds to 10 be memorised?

Yes, to the point of instant recall. The five pairs from 1+9 to 5+5 are the prerequisite for make-ten.

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