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Primary 2 Maths: Multiplication and Division — Practice Paper 1 (10 Questions)

Primary 2 Maths: Multiplication and Division — Practice Paper 1 (10 Questions)

  • 2026-10-29

Primary 2 Maths: Multiplication and Division — Practice Paper 1 (10 Questions)

Paper 1 follows the lesson plan: arrays for “so many rows of so many”, the 5 and 10 times tables, equal sharing, and division with a remainder. Every item shows its check.

Quick answer 10 questions, about 20 minutes. Items 01 to 04 cover what multiplication means and table division, items 05 to 07 are table division and multiplication, items 08 and 09 are a remainder problem and bagging, item 10 targets a remainder larger than the divisor.

01 Paper details (check answers afterwards)

Item Detail
Questions 10 questions
Suggested time 20 minutes
Difficulty mix Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1
Chapter Chapter: Primary 2 Maths: Multiplication and Division — Tutor Lesson Plan
Level Primary 2

02 Questions (10 items)

  1. FoundationFour rows of 6 counters. How many altogether? Write the multiplication and the answer.
  2. FoundationWork out: 5 × 8
  3. FoundationWork out: 10 × 7
  4. Foundation12 sweets are shared into 3 equal groups. How many in each group?
  5. IntermediateWork out: 45 ÷ 5
  6. IntermediateWork out 23 ÷ 4 and give the quotient and remainder.
  7. IntermediateWork out: 9 × 4
  8. Challenge34 beads, 6 beads to a string. How many full strings, and how many beads left over?
  9. Challenge30 sweets, 5 to a bag. How many bags?
  10. Error redoWork out: 29 ÷ 4 (common slip: answering 6 remainder 5, a remainder larger than the divisor)

03 Answers and one-line notes

# Answer One-line note
1 4 × 6 = 24 counters “So many rows of so many” is multiplication: four 6s make 24, the same as 6 + 6 + 6 + 6.
2 40 The 5 times table goes up by 5 each time; the eighth number is 40.
3 70 Multiplying by 10 puts a zero after the number: 7 becomes 70.
4 4 sweets Sharing uses division: 12 ÷ 3 = 4, and 4 × 3 = 12 checks it.
5 9 Ask “5 times what makes 45”: 5 × 9 = 45, so the answer is 9 with no remainder.
6 5 remainder 3 4 × 5 = 20 and 23 − 20 = 3, so 5 remainder 3, and 3 is smaller than 4 as it must be.
7 36 9 × 4 is four 9s: 9 + 9 + 9 + 9 = 36, or 4 × 10 minus 4.
8 5 strings with 4 left 6 × 5 = 30 and 34 − 30 = 4, so 5 strings with 4 left; 6 × 6 = 36 is past 34, so a sixth string is impossible.
9 6 bags 30 ÷ 5 = 6, and 6 × 5 = 30 checks it; the bags are exact, so there is no remainder.
10 7 remainder 1 4 × 7 = 28 and 29 − 28 = 1, so 7 remainder 1. A remainder must be smaller than the divisor; 5 left over means another group can still be made.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

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Questions and answers are written originally by the TutorZone team and are not taken from any school, publisher or examination authority paper. Every value is checked by computer.