Primary 2 Maths: Multiplication and Division — Practice Paper 1 (10 Questions)
Paper 1 follows the lesson plan: arrays for “so many rows of so many”, the 5 and 10 times tables, equal sharing, and division with a remainder. Every item shows its check.
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | 20 minutes |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: Primary 2 Maths: Multiplication and Division — Tutor Lesson Plan |
| Level | Primary 2 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 4 × 6 = 24 counters | “So many rows of so many” is multiplication: four 6s make 24, the same as 6 + 6 + 6 + 6. |
| 2 | 40 | The 5 times table goes up by 5 each time; the eighth number is 40. |
| 3 | 70 | Multiplying by 10 puts a zero after the number: 7 becomes 70. |
| 4 | 4 sweets | Sharing uses division: 12 ÷ 3 = 4, and 4 × 3 = 12 checks it. |
| 5 | 9 | Ask “5 times what makes 45”: 5 × 9 = 45, so the answer is 9 with no remainder. |
| 6 | 5 remainder 3 | 4 × 5 = 20 and 23 − 20 = 3, so 5 remainder 3, and 3 is smaller than 4 as it must be. |
| 7 | 36 | 9 × 4 is four 9s: 9 + 9 + 9 + 9 = 36, or 4 × 10 minus 4. |
| 8 | 5 strings with 4 left | 6 × 5 = 30 and 34 − 30 = 4, so 5 strings with 4 left; 6 × 6 = 36 is past 34, so a sixth string is impossible. |
| 9 | 6 bags | 30 ÷ 5 = 6, and 6 × 5 = 30 checks it; the bags are exact, so there is no remainder. |
| 10 | 7 remainder 1 | 4 × 7 = 28 and 29 − 28 = 1, so 7 remainder 1. A remainder must be smaller than the divisor; 5 left over means another group can still be made. |
Questions and answers are written originally by the TutorZone team and are not taken from any school, publisher or examination authority paper. Every value is checked by computer.

