Primary 5 Maths: Area of Triangles, Parallelograms and Trapeziums — Tutor Lesson Plan
- 2026-10-27
Two failures dominate: forgetting to halve the triangle, and using the slant side as the height. This lesson shows where the formulas come from, then drills “which line is the height”.
01 Prerequisites (3-minute check)
If any of these fails, fix it before the lesson starts.
| Skill | Quick check | Pass mark |
|---|---|---|
| Rectangle area | Length 8 cm, width 5 cm | 40 cm², with units |
| Multiplication and division | 96 ÷ 2 | 48 |
| Parallel lines | Is the distance between parallel lines constant? | Yes |
02 Lesson flow (45 minutes)
| Time | Stage | Tutor does | Student does |
|---|---|---|---|
| 0-6 min | Cut and rearrange | Cut a parallelogram into a rectangle | Cut along and check the area is unchanged |
| 6-16 min | Three formulas | Derive parallelogram, triangle, trapezium | Write each formula and its origin |
| 16-26 min | Choose the height | Three diagrams: which line is the height? | Mark the right angle on each |
| 26-36 min | Practice | Three questions including one backwards | Work alone, write the formula line |
| 36-42 min | Fix errors | Board the slant-side error | Say which step failed |
| 42-45 min | Exit check | Three questions marked at once | Finish alone |
03 Teaching script (read it out)
Scene 1: Parallelogram is a rectangle
Length equals base, width equals height, so area = base × height.
Repeat: “The area did not change, so base times height is the area.”
Scene 2: Triangle is half of it
The ÷2 comes from there, it is not a rule to memorise.
Student points at the base and the height and says “the height is perpendicular”.
Scene 3: Trapezium is half of a bigger parallelogram
So area = (a + b) × height ÷ 2.
Warn: the trapezium also needs ÷2; students often halve only triangles.
04 Question types and worked steps
| Type | Example | Steps | Answer |
|---|---|---|---|
| Triangle | base 8, height 5 | 8 × 5 ÷ 2 | 20 cm² |
| Parallelogram | base 7, height 4 | 7 × 4 | 28 cm² |
| Trapezium | a = 6, b = 10, height 4 | (6 + 10) × 4 ÷ 2 | 32 cm² |
| Backwards | triangle area 30, base 10 | 30 × 2 ÷ 10 | height 6 |
05 Independent practice (3 questions)
| Question | Answer | What to watch |
|---|---|---|
| Triangle base 12, height 7 | 42 cm² | Halving and units |
| Parallelogram base 9, height 6 | 54 cm² | Using the slant side? |
| Trapezium a = 5, b = 9, height 8 | 56 cm² | Adding both bases |
06 Common mistakes and what to say
| Mistake | Student writes | Say this |
|---|---|---|
| Triangle not halved | 8 × 5 = 40 | A triangle is half the parallelogram: divide by 2. |
| Slant side used as height | 7 × 5 on the slant | The height is perpendicular to the base, marked with a right angle. |
| Trapezium not halved | (6 + 10) × 4 = 64 | Trapeziums also divide by 2. |
| Wrong unit | answer in cm | Area is in square centimetres. |
07 Homework (paper, section and question numbers)
- Primary 5 first-term paper — Section C, questions 1 to 5
- Primary 5 second-term paper — Section C, questions 1 to 4
08 Exit check (last 5 minutes)
| Question | Answer | Decision |
|---|---|---|
| Triangle base 15, height 8 | 60 cm² | All right: move to volume |
| Trapezium a = 4, b = 8, height 5 | 30 cm² | One wrong: re-teach that formula |
| Triangle area 48, base 12: height? | 8 cm | Two wrong: repeat the cutting activity |
09 Tutor FAQ
Is the cutting activity necessary?
Yes. It takes five minutes and answers “where does the ÷2 come from” once and for all.
Students cannot find the height.
Look for the right-angle mark first, then the base it touches; with no mark, ask for the perpendicular distance.
Do you teach composite shapes?
Not here. Composite shapes need all three formulas solid first.
A TutorZone lesson-prep guide. Written by the TutorZone team; questions and lesson flow are original and are not taken from any school or publisher material.


