Primary 5 Maths: Simple Equations — Practice Paper 4 (10 Questions)
Paper 4 completes the set of four: equations where x is the part taken away (28 − x = 11, 56 − 4x = 24), plus 7x − 19 = 44, a change problem and “six times minus nine”. Check every answer by substitution.
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | 25 minutes |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: Primary 5 Maths: Simple Equations — Tutor Lesson Plan |
| Level | Primary 5 |
| # | Answer | One-line note |
|---|---|---|
| 1 | x = 37 | Subtract 34 from both sides: x = 71 − 34 = 37, and 37 + 34 = 71 checks it. |
| 2 | x = 71 | Add 26 to both sides: x = 45 + 26 = 71, and 71 − 26 = 45 checks it. |
| 3 | x = 13 | 9x is nine x, so divide both sides by 9: x = 117 ÷ 9 = 13, and 9 × 13 = 117. |
| 4 | x = 96 | x is divided by 8, so multiply both sides by 8: x = 12 × 8 = 96, and 96 ÷ 8 = 12. |
| 5 | x = 11 | Subtract 16 for 3x = 33, then divide by 3 for x = 11; 3 × 11 + 16 = 49. |
| 6 | x = 9 | Add 19 for 7x = 63, then divide by 7 for x = 9; 7 × 9 − 19 = 44. |
| 7 | x = 17 | 28 minus x leaves 11, so x is the gap between them: x = 28 − 11 = 17, and 28 − 17 = 11. |
| 8 | 5 pens cost $30, so x − 30 = 18 and x = 48 | Five pens cost 5 × 6 = $30; taking that from the money gives 18: x − 30 = 18, so x = 48. |
| 9 | 6x − 9 = 63, so x = 12 | “Six times minus 9” becomes 6x − 9: add 9 for 6x = 72, divide by 6 for x = 12; 6 × 12 − 9 = 63. |
| 10 | x = 8 | 4x is the part being taken away, so 4x = 56 − 24 = 32 and x = 8; 56 − 4 × 8 = 24. |
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