Primary 5 Maths: Volume of Cuboids and Cubes — Practice Paper 2 (10 Questions)
Paper 2 starts from counting layers and only then uses the formula: litre conversion, tanks filled to a fraction, cutting with a remainder and joined solids are the variations school tests use.
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | 25 minutes |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: Primary 5 Maths: Volume of Cuboids and Cubes |
| Level | Primary 5 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 180 cm³ | Length × width × height. |
| 2 | 343 cm³ | All edges equal: 7 × 7 × 7. |
| 3 | 288 cm³ | Volume = base area × height; the base area already stands for length × width. |
| 4 | 240 cubes | Counting layer by layer is where the formula comes from: 30 × 8. |
| 5 | 3 L | 1 L = 1000 cm³, so divide by 1000. |
| 6 | 1.0 m | Height = volume ÷ (length × width) = 0.72 ÷ 0.72. |
| 7 | 20 L | Full capacity is 30,000 cm³; × 2/3 gives 20,000 cm³, then ÷ 1000. |
| 8 | 24 cubes, with 1 cm of height unused | 8 ÷ 2 = 4, 6 ÷ 2 = 3, 5 ÷ 2 = 2 with 1 left, so 4 × 3 × 2 = 24; the last 1 cm cannot form a full cube. |
| 9 | 120 cm³ | Work each out and add: 72 + 48 = 120; joining does not change volume. |
| 10 | 30 cm³ | 5 × 3 = 15 is only the bottom layer; multiply by the height 2 as well. |
Questions and answers are written originally by the TutorZone team and are not taken from any school, publisher or examination authority paper. Every value is checked by computer.

