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Primary 6 Maths: Percentage Applications — Tutor Lesson Plan (increase, decrease, discount)

Primary 6 Maths: Percentage Applications — Tutor Lesson Plan (increase, decrease, discount)

  • 2026-10-27

Every percentage question has one key: what counts as 100%. Students who name the base first stop making sign and division errors.

Objectives — the student can name the base amount, compute an increase, a decrease and a discount, find the original price from a sale price, and use a single multiplier.

01 Prerequisites (3-minute check)

If any of these fails, fix it before the lesson starts.

Skill Quick check Pass mark
Meaning of percent What is 25%? 25 out of 100, or 0.25
Fraction to percent 3/4 as a percentage 75%
Multiplication 480 × 0.25 120

02 Lesson flow (50 minutes)

Time Stage Tutor does Student does
0-6 min Name the base Ask “10% more of what?” Answer: of the original price
6-16 min Find a percentage Show 25% of 480 Two alone
16-28 min Increase and decrease 80 plus 15%, 60 minus 25% One each
28-38 min Original price Sale price 85 at 20% off One alone
38-46 min Fix errors Board “up 20% then down 20%” Explain why it does not return
46-50 min Exit check Three questions marked at once Finish alone

03 Teaching script (read it out)

Scene 1: What is the 100%?

“10% more” means 10% of the original, so the original is 100% and the new price is 110%.
Write the base amount before touching the calculator.

Student answers that a discount is a percentage of the original price.

Scene 2: One multiplier beats two steps

80 increased by 15% is 80 × 1.15 = 92.
Two steps also work, 80 + 12, but one multiplication has fewer places to slip.

Student does 120 × 0.85 = 102.

Scene 3: Original price: divide, do not add

Sale price 85 at 20% off means original × 0.8 = 85, so original = 85 ÷ 0.8 = 106.25.
Adding 20% to 85 gives a different number.

Warn: up 20% then down 20% does not return to the start, because the second base changed.

04 Question types and worked steps

Type Example Steps Answer
Percentage of 25% of 480 480 × 0.25 120
Increase 80 plus 15% 80 × 1.15 92
Decrease or discount 60 minus 25% 60 × 0.75 45
Original price 85 after 20% off 85 ÷ 0.8 106.25
Sanity check (teach this): An increase always ends above the original and a discount always below; a discount price higher than the original means the division used the wrong multiplier.

05 Independent practice (3 questions)

Question Answer What to watch
40% of 250 100 Converting to 0.4
120 minus 15% 102 Using 0.85 in one step
50 raised to 60: percentage increase 20% Base is 50

06 Common mistakes and what to say

Mistake Student writes Say this
Wrong base using the sale price as 100% A discount is a percentage of the original.
Adding the percentage as a number 80 plus 15% written as 80 + 15 15% of 80 is 12, not 15.
Adding to reverse a discount 85 at 20% off becomes 85 + 17 Divide by 0.8 instead.
Assuming percentages cancel up 20% then down 20% returns to the start The base changes, so the result is 4% lower.

07 Homework (paper, section and question numbers)

08 Exit check (last 5 minutes)

Question Answer Decision
40% of 250 100 All right: move to circle area
120 minus 15% 102 One wrong: re-teach the base
Percentage increase from 50 to 60 20% Two wrong: repeat scene 1

09 Tutor FAQ

Should they use ×1.15?

Yes in Primary 6, but keep the two-step version alive so the meaning is clear.

Discounts in a separate lesson?

No, a discount is just a decrease; one lesson reduces confusion.

Interest and tax?

Not required at this level.

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A TutorZone lesson-prep guide. Written by the TutorZone team; questions and lesson flow are original and are not taken from any school or publisher material.