S1 Maths | Linear Equations and Word Problems Lesson Prep Guide (for tutors) | Balancing, brackets and forming equations
- 2026-11-09
An equation is not about moving numbers around; it is about doing the same thing to both sides. Once students hold that sentence, transposing stops being a chant.
01 Prerequisites (3-minute check)
If any of these fails, fix it before the lesson starts.
| Skill | Quick check | Pass mark |
|---|---|---|
| Negative arithmetic | What is 5 minus 8? | -3 |
| Substitution | When x is 5, what is 3x plus 5? | 20 |
| Fractions | What is half of 8? | 4 |
02 Lesson flow (60 minutes)
| Time | Stage | Tutor does | Student does |
|---|---|---|---|
| 0-6 min | An equation is a balance | 3x plus 5 equals 20: subtract 5 from both sides, then divide both sides by 3 | State what each move did |
| 6-16 min | Two-step equations and checking | x is 5; substituting back gives 20, so both sides agree | Solve one and check it |
| 16-28 min | Brackets, denominators, negatives | 3(x minus 2) equals 12: divide first; 5 minus 2x equals 11 gives x equals minus 3 | Three questions in pairs |
| 28-40 min | Unknowns on both sides | 4x minus 7 equals x plus 11; subtract x from both sides, then move the constant, giving 6 | Collect the unknown on one side |
| 40-54 min | Forming the equation | Adult tickets 60, child tickets 40, 12 tickets for 560: 4 adults and 8 children | Form and solve independently |
| 54-60 min | Exit check | Three oral questions; any miss points to the stage to reteach | Oral answers |
03 Teaching script (read it out)
Scene 1: A balance, not a shuffle
Teaching move: make students draw a vertical line at the equals sign and annotate “minus 5 both sides”, “divide by 3 both sides”, so a slip is visible at once.
Students do: solve 3x plus 5 equals 20 and substitute the answer back, writing that both sides equal 20.
Scene 2: Brackets first, denominators last
Teaching move: always ask whether the number outside the bracket divides the other side exactly; if it does, divide first and halve the size of every number.
Students do: solve 3(x minus 2) equals 12 twice, once by dividing first and once by expanding.
Scene 3: Negative coefficients: predict the sign first
Teaching move: before dividing, require one written prediction saying the answer should be negative or positive, then compare after computing.
Students do: solve 5 minus 2x equals 11 and explain why the answer is negative.
Scene 4: Word problems: define the unknown first
Teaching move: enforce three written lines before any algebra — define the unknown, write the total count, write the total value.
Students do: three consecutive integers sum to 45; let the middle be n, form the equation and find 14, 15 and 16.
04 Question types and worked steps
| Type | Example | Steps | Answer |
|---|---|---|---|
| Two-step equation | 3x plus 5 equals 20 | Add or subtract first, then multiply or divide, annotating each move | x equals 5 |
| With brackets | 3(x minus 2) equals 12 | Divide first if it divides exactly, otherwise expand | x equals 6 |
| Unknown on both sides | 4x minus 7 equals x plus 11 | Subtract the smaller x term from both sides to avoid negatives | x equals 6 |
| Word problem | Tickets at 60 and 40, 12 sold for 560 | One unknown, the other as the total minus it, then a value equation | 4 adults and 8 children |
05 Independent practice (3 questions)
| Question | Answer | What to watch |
|---|---|---|
| Four two-step equations | Include one negative coefficient and one fraction | Is each move annotated |
| Two bracket questions | One dividing first, one expanding first | Was the second term multiplied |
| Two word problems | Tickets and consecutive integers | Is the unknown defined and the unit stated |
06 Common mistakes and what to say
| Mistake | Student writes | Say this |
|---|---|---|
| Forgetting to change the sign | Writing 3x equals 20 plus 5 from 3x plus 5 equals 20 | Moving a term is subtracting 5 from both sides, so the right side loses 5 as well; it does not gain it. |
| Multiplying only the first term | Writing 3(x minus 2) as 3x minus 2 | The number outside the bracket multiplies every term inside; draw arrows from it to both terms before expanding. |
| Dropping the sign on division | Getting a positive answer from minus 2x equals 6 | Dividing both sides by a negative number flips the sign of the whole result; say “the unknown is negative” before writing. |
| No defined unknown in word problems | Writing an equation without saying what the letter means | Without a definition the final number means nothing; three lines: a is adult tickets, children are 12 minus a, the total is 560 dollars. |
07 Homework (paper, section and question numbers)
- Secondary maths chapter index — See the other chapters in this subject
- Lesson prep guides home — Compare related chapters
- Redo this chapter — Redo diagnostic questions 1 to 6, annotating each move
08 Exit check (last 5 minutes)
| Question | Answer | Decision |
|---|---|---|
| x in 3x plus 5 equals 20 | 5 | Answering minus 5 means sign errors on transposing; reteach stage one |
| x in 4x minus 7 equals x plus 11 | 6 | Answering 4 means x was not subtracted from both sides; reteach stage four |
| Adults among 12 tickets | 4 | Answering 8 means the unknown was defined the wrong way round; reteach stage four |
09 Tutor FAQ
Must every answer be checked?
In an exam a quick substitution in the margin is enough, but do it: one minute of checking beats losing a whole question.
Can both sides be multiplied?
Yes, by any non-zero number; that is exactly why multiplying both sides by the denominator clears fractions safely.
Must word-problem answers be whole numbers?
Not always, but counts of tickets, people or items must be positive integers; a fraction means the equation or the reading is wrong.
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A TutorZone lesson-prep guide. Written by the TutorZone team; questions and lesson flow are original and are not taken from any school or publisher material.


