S4 Biology: Ecosystems and Energy Flow (Paper 4)
- 2026-11-01
S4 Biology: Ecosystems and Energy Flow (Paper 4)
The fourth paper pulls the chapter together: the ten per cent rule, energy budgets, reverse calculations and bioaccumulation, ending with a gross versus net productivity error.
Direct answer Write out the energy at each level, then multiply or divide by the efficiency as required; whenever the word net appears, subtract plant respiration first.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 25 |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: S4 Biology: Ecosystems and Energy Flow |
| Level | Four basic, three advanced, two challenge and one error-repair item |
02 Questions (10 items)
- FoundationGrass holds 80 000 kJ and the rabbit gains one tenth of it. How much does the rabbit gain?
- FoundationThe rabbit takes in 8 000 kJ and 800 kJ reaches the fox. What is the transfer efficiency?
- FoundationGross primary productivity is 12 000 kJ/m2/yr and plant respiration uses 4 500 kJ/m2/yr. What is net primary productivity?
- FoundationCattle take in 6 000 kJ, respire 3 600 kJ and pass 1 200 kJ as faeces. What percentage of intake goes to growth?
- IntermediateA five-level chain starts with 500 000 kJ and keeps one tenth at each transfer. How much reaches the fifth level?
- IntermediateTwo ecosystems each receive 2 000 kJ from producers, transferring 15 and 6 per cent. How much more does the first pass on?
- IntermediateThe fox gains only 300 kJ and the rabbit to fox efficiency is ten per cent. How much did the rabbit hold?
- ChallengeDDT in water is 0.0005 ppm and magnifies tenfold at each of three levels. What is the concentration in the top consumer?
- ChallengeWhy can the same grassland support more people than cattle?
- Error redoAsked for net primary productivity with gross 9 000 and respiration 3 000, a student answers 9 000. What is correct?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | 8 000 kJ | About one tenth passes on, so 80 000 x 10% = 8 000 kJ. |
| 2 | 10 per cent | 800 out of 8 000 is 10 per cent; the other nine tenths is lost as heat from respiration. |
| 3 | 7 500 kJ/m2/yr | Net primary productivity is gross productivity minus plant respiration, giving 7 500. |
| 4 | 20 per cent | Subtracting respiration and faeces leaves 1 200 kJ, which is 20 per cent of intake. |
| 5 | 50 kJ | Four transfers give 500 000 x 0.1 to the fourth power, only 50 kJ, so chains rarely exceed five levels. |
| 6 | 180 kJ | One yields 300 kJ and the other 120 kJ, a gap of 180 kJ from a nine point efficiency difference. |
| 7 | 3 000 kJ | Working backwards, 300 divided by 0.10 gives 3 000 kJ, so reverse questions always use division. |
| 8 | 0.5 ppm | Three tenfold steps give 0.5 ppm, a thousandfold build-up that puts top consumers most at risk. |
| 9 | People eating plants sit one level lower, and each extra level loses about nine tenths of the energy | Each extra level loses about nine tenths of the energy, so eating plants directly supports more people. |
| 10 | 6 000 kJ/m2/yr | Net productivity must subtract plant respiration, so 9 000 minus 3 000 gives 6 000; 9 000 is only the gross figure. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
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