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DSE Chemistry: Acids and Bases — Tutor Lesson Plan (pH, neutralisation, titration)

DSE Chemistry: Acids and Bases — Tutor Lesson Plan (pH, neutralisation, titration)

  • 2026-10-27

Titration marks are lost in the unit conversion, not the formula. Drill one move: turn cm3 into dm3, then multiply by concentration.

Objectives — the student can define acids and bases, compute pH from concentration, and complete neutralisation calculations using mole ratios.

01 Prerequisites (3-minute check)

If any of these fails, fix it before the lesson starts.

Skill Quick check Pass mark
Moles How many cm3 in 1 dm3? 1000
Concentration What does 0.1 M mean? 0.1 mol per dm3
Logarithms Negative log of 10 to the minus 2 2

02 Lesson flow (60 minutes)

Time Stage Tutor does Student does
0-10 min Definitions Proton donor and acceptor Four examples
10-24 min pH and indicators pH = -log[H+] Three values
24-40 min Neutralisation H+ plus OH- gives water Three equations
40-54 min Titration Mole ratio and concentration Two calculations
54-57 min Format Equation first, then moles Rewrite one
57-60 min Exit check Three questions marked Finish alone

03 Teaching script (read it out)

Scene 1: Acids donate, bases accept

Hydrochloric and sulfuric acid are strong; sodium hydroxide is a strong base; ammonia is weak.
Strong acids ionise fully, weak acids partly, so equal concentrations give different pH.

Student states which has the lower pH: 0.1 M HCl or 0.1 M ethanoic acid.

Scene 2: pH only reads hydrogen ion concentration

pH = -log[H+]. A 0.01 M strong acid has pH 2.
Each unit is a tenfold change, so diluting tenfold raises pH by about 1.

Student computes the pH of 0.001 M HCl: 3.

Scene 3: Titration: the equation gives the ratio

HCl + NaOH gives NaCl + water, one to one.
0.1 M HCl, 25 cm3, is 0.0025 mol, needing 25 cm3 of 0.1 M NaOH.
With sulfuric acid and two hydroxides the ratio is one to two, so double the base.

Note: write the equation before touching the numbers.

04 Question types and worked steps

Type Example Steps Answer
pH 0.01 M HCl pH = -log(0.01) 2
Neutralisation volume 0.1 M HCl 25 cm3 with 0.1 M NaOH One to one 25 cm3
Mole ratio H2SO4 with NaOH One to two Double the base
Indicator Strong acid with strong base Phenolphthalein, colourless to pink End point near pH 7
Sanity check (teach this): For a one-to-one titration the moles of acid must equal the moles of base; a factor of two means the ratio was ignored.

05 Independent practice (3 questions)

Question Answer What to watch
pH of 0.001 M HCl 3 Negative log of 10 to the minus 3
0.05 M NaOH 25 cm3 needs how much 0.1 M HCl 12.5 cm3 One to one ratio
pH after tenfold dilution Rises by 1 Concentration falls tenfold

06 Common mistakes and what to say

Mistake Student writes Say this
Multiplying cm3 by concentration directly skips dm3 Divide by 1000 first.
Ignoring the equation ratio treats sulfuric acid as one to one Count the hydrogen ions.
Reading pH as concentration says pH 2 means 2 M pH is a negative logarithm.
Wrong indicator methyl orange for strong acid and base Phenolphthalein is standard.

07 Homework (paper, section and question numbers)

08 Exit check (last 5 minutes)

Question Answer Decision
pH of 0.001 M HCl 3 All right: move to redox
0.05 M NaOH 25 cm3 with 0.1 M HCl 12.5 cm3 One wrong: re-teach moles
pH after tenfold dilution Rises by 1 Two wrong: repeat scene 3

09 Tutor FAQ

Memorise strong acids?

Hydrochloric, sulfuric, nitric; and two strong bases.

Weak acid pH?

Compare only for DSE.

Titration errors?

Rinsing, reading the burette, indicator choice.

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A TutorZone lesson-prep guide. Written by the TutorZone team; questions and lesson flow are original and are not taken from any school or publisher material.