S4 Chemistry: Periodic Table and Trends Paper 3 (Data Inference, Isoelectronic Series and Transition Metals)
- 2026-11-03
S4 Chemistry: Periodic Table and Trends Paper 3 (Data Inference, Isoelectronic Series and Transition Metals)
This paper infers group number from ionisation-energy jumps, ranks a 10-electron isoelectronic series, and extends to transition-metal features and group-trend predictions.
Quick answer 1. argon is full-shell, potassium has one fourth-shell electron | 2. group II | 3. a 10-electron isoelectronic series | 4. Z = 20, period 4 group II | 5. variable valency, catalysis, colour | 6. more violent than potassium | 7. more delocalised electrons | 8. Ca2+ < Na+ < K+ | 9. period 5 group I, a metal | 10. it should increase down the group
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | 25 minutes |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: S4 Chemistry – Periodic Table and Trends |
| Level | Challenge |
02 Questions (10 items)
- FoundationName three typical features that separate transition metals from main-group metals.
- FoundationPredict whether rubidium reacts with water more or less violently than potassium, and explain.
- FoundationThe ion X2+ has 18 electrons. What is the atomic number of X, and its period and group?
- FoundationAn element has the arrangement 2, 8, 18, 8, 1. Give its period, group and type.
- IntermediateNa+ 102 pm, Mg2+ 72 pm, Al3+ 54 pm, F- 133 pm. What do these ions share?
- IntermediateWhy does metallic conductivity generally improve down a group?
- IntermediateRadii: Na+ 102 pm, K+ 138 pm, Ca2+ 100 pm. Order them from smallest to largest with a reason.
- ChallengeArgon first ionisation energy (1520 kJ/mol) far exceeds potassium (419) although potassium has the larger atomic number. Why?
- ChallengeAn element has first four ionisation energies of 590, 1150, 4940 and 6480 kJ/mol. Which group?
- Error redoA student wrote “radius shrinks down a group because nuclear charge increases”. Correct it.
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | Variable oxidation states, common catalysts, and coloured compounds | Inner d electrons can take part, giving several oxidation states. |
| 2 | More violently; rubidium sits below potassium, with a larger radius and lower ionisation energy | Extrapolating a group trend is the standard prediction question. |
| 3 | Atomic number 20; period 4, group II (calcium) | Add the two lost electrons back to get 20, then write 2, 8, 8, 2. |
| 4 | Period 5, group I; a metal (rubidium) | Five shells means period 5; one outer electron means group I. |
| 5 | All are 10-electron isoelectronic species; the larger the nuclear charge, the smaller the radius | With equal electrons, proton count decides the pull. |
| 6 | Outer electrons are released more easily, giving more delocalised electrons and stronger metallic bonding | Metallic character and conductivity rise together from easier electron loss. |
| 7 | Ca2+ (100) < Na+ (102) < K+ (138); higher charge and fewer shells mean smaller | Compare both shell count and charge, not one alone. |
| 8 | Argon has a full outer shell and small radius; potassium has a single fourth-shell electron, far out and well shielded | Compare shell number and shielding, not atomic number alone. |
| 9 | Group II; the jump comes at the third electron, so there are two valence electrons | The jump index is the valence count plus one, the standard way to read the group. |
| 10 | Radius grows down a group; the extra shell outweighs the extra nuclear charge | Extra nuclear charge dominates across a period, but a new shell dominates down a group. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
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