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S4 Chemistry: Redox and Electrolysis (Paper 3)

S4 Chemistry: Redox and Electrolysis (Paper 3)

  • 2026-10-31

S4 Chemistry: Redox and Electrolysis (Paper 3)

This paper moves into electrolytic cells: anode oxidation, cathode reduction, then products from charge.

Direct answer Find the moles of electrons first, then use the electron ratio in the half-equation.

01 Paper details (check answers afterwards)

Item Detail
Questions 10
Suggested time 25
Difficulty mix Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1
Chapter Chapter: S4 Chemistry: Redox and Electrolysis
Level Four basic, three advanced, two challenge and one error-repair item

02 Questions (10 items)

  1. FoundationElectrolysing copper(II) sulphate with copper electrodes: what happens at the anode?
  2. FoundationWhich gas appears at the cathode when dilute sulphuric acid is electrolysed and what is the half-equation?
  3. FoundationWhat product forms at the anode when molten sodium chloride is electrolysed?
  4. FoundationElectrolysing copper(II) chloride solution with inert electrodes: give the anode half-equation.
  5. IntermediateA current of 0.500 A flows for 965 s. What mass of copper is deposited at the cathode, with Cu = 63.5?
  6. IntermediateWith 2.00 A for 1 930 s, what volume of hydrogen forms at room temperature, molar volume 24.0 dm3 mol-1?
  7. IntermediateElectroplating needs 3.175 g of copper at the cathode. What charge is required, with Cu = 63.5?
  8. ChallengeGive the overall equation for electrolysing concentrated brine and name the cathode product.
  9. ChallengeElectrolysing copper(II) sulphate with inert electrodes passes 0.0200 mol of electrons. How much of each product forms?
  10. Error redoError repair: a student writes that the anode always gives metal during electrolysis. Correct it.

03 Answers and one-line notes

# Answer One-line note
1 Cu gives Cu2+ + 2e- A copper anode is an active electrode, so the metal itself is oxidised into solution.
2 hydrogen; 2H+ + 2e- gives H2 Reduction occurs at the cathode, where hydrogen ions gain electrons to form hydrogen gas.
3 chlorine gas No water is present in the melt, so chloride ions are oxidised to chlorine at the anode.
4 2Cl- gives Cl2 + 2e- Inert electrodes take no part, so chloride ions, the easiest to oxidise, release electrons first.
5 about 0.159 g The charge is 482.5 C, which is 0.00500 mol of electrons, so copper at two electrons each gives 0.1588 g.
6 about 480 cm3 The charge gives 0.0400 mol of electrons, so hydrogen at two electrons each is 0.0200 mol, or 0.480 dm3.
7 9 650 C 3.175 g is 0.0500 mol of copper, which needs 0.100 mol of electrons and therefore 9 650 C.
8 2NaCl + 2H2O gives 2NaOH + H2 + Cl2; hydrogen at the cathode Water is reduced at the cathode, releasing hydrogen and leaving hydroxide ions, while chloride is oxidised to chlorine.
9 cathode 0.0100 mol of copper; anode 0.00500 mol of oxygen Copper takes two electrons for 0.0100 mol, or 0.635 g, while oxygen takes four for 0.00500 mol.
10 the anode is where oxidation happens; metals deposit at the cathode The anode loses electrons while metal ions must gain them, so metals appear at the cathode.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

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