S4 Chemistry: Redox and Electrolysis (Paper 3)
- 2026-10-31
S4 Chemistry: Redox and Electrolysis (Paper 3)
This paper moves into electrolytic cells: anode oxidation, cathode reduction, then products from charge.
Direct answer Find the moles of electrons first, then use the electron ratio in the half-equation.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 25 |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: S4 Chemistry: Redox and Electrolysis |
| Level | Four basic, three advanced, two challenge and one error-repair item |
02 Questions (10 items)
- FoundationElectrolysing copper(II) sulphate with copper electrodes: what happens at the anode?
- FoundationWhich gas appears at the cathode when dilute sulphuric acid is electrolysed and what is the half-equation?
- FoundationWhat product forms at the anode when molten sodium chloride is electrolysed?
- FoundationElectrolysing copper(II) chloride solution with inert electrodes: give the anode half-equation.
- IntermediateA current of 0.500 A flows for 965 s. What mass of copper is deposited at the cathode, with Cu = 63.5?
- IntermediateWith 2.00 A for 1 930 s, what volume of hydrogen forms at room temperature, molar volume 24.0 dm3 mol-1?
- IntermediateElectroplating needs 3.175 g of copper at the cathode. What charge is required, with Cu = 63.5?
- ChallengeGive the overall equation for electrolysing concentrated brine and name the cathode product.
- ChallengeElectrolysing copper(II) sulphate with inert electrodes passes 0.0200 mol of electrons. How much of each product forms?
- Error redoError repair: a student writes that the anode always gives metal during electrolysis. Correct it.
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | Cu gives Cu2+ + 2e- | A copper anode is an active electrode, so the metal itself is oxidised into solution. |
| 2 | hydrogen; 2H+ + 2e- gives H2 | Reduction occurs at the cathode, where hydrogen ions gain electrons to form hydrogen gas. |
| 3 | chlorine gas | No water is present in the melt, so chloride ions are oxidised to chlorine at the anode. |
| 4 | 2Cl- gives Cl2 + 2e- | Inert electrodes take no part, so chloride ions, the easiest to oxidise, release electrons first. |
| 5 | about 0.159 g | The charge is 482.5 C, which is 0.00500 mol of electrons, so copper at two electrons each gives 0.1588 g. |
| 6 | about 480 cm3 | The charge gives 0.0400 mol of electrons, so hydrogen at two electrons each is 0.0200 mol, or 0.480 dm3. |
| 7 | 9 650 C | 3.175 g is 0.0500 mol of copper, which needs 0.100 mol of electrons and therefore 9 650 C. |
| 8 | 2NaCl + 2H2O gives 2NaOH + H2 + Cl2; hydrogen at the cathode | Water is reduced at the cathode, releasing hydrogen and leaving hydroxide ions, while chloride is oxidised to chlorine. |
| 9 | cathode 0.0100 mol of copper; anode 0.00500 mol of oxygen | Copper takes two electrons for 0.0100 mol, or 0.635 g, while oxygen takes four for 0.00500 mol. |
| 10 | the anode is where oxidation happens; metals deposit at the cathode | The anode loses electrons while metal ions must gain them, so metals appear at the cathode. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
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