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S4 ICT | Data Representation and File Size Lesson Prep Guide (for tutors) | Sampling, resolution and compression

S4 ICT | Data Representation and File Size Lesson Prep Guide (for tutors) | Sampling, resolution and compression

  • 2026-11-09

This chapter has only three formulas, yet the marks are lost by reading kHz as Hz and 24-bit as 24 Byte.

Objectives — Students can: (1) state the bit, Byte, KB and MB relationships and convert correctly; (2) compute file size with width times height times colour depth divided by eight, and sampling rate times bit depth divided by eight times channels times seconds; (3) explain Nyquist sampling and the difference between lossy and lossless compression, scoring at least 9 of 12 in the diagnostic.

01 Prerequisites (3-minute check)

If any of these fails, fix it before the lesson starts.

Skill Quick check Pass mark
Unit relations How many bits in a Byte? How many KiB in a MiB? 8; 1024
Multiplication What is 1920 times 1080? 2073600
Percentages What percentage of 1000 is 90? 9 percent

02 Lesson flow (60 minutes)

Time Stage Tutor does Student does
0-6 min The unit ladder bit, Byte, KiB, MiB, GiB, marking times eight or times 1024 at each step Write the ladder and convert two values
6-16 min Image size 1920 by 1080 at 24-bit is 6,220,800 Byte, about 5.93 MiB Repeat for 1280 by 720
16-30 min Audio size 44.1 kHz, 16-bit, stereo, 180 seconds gives 31,752,000 Byte, about 30.28 MiB Repeat in mono
30-42 min Sampling and compression Nyquist needs twice the top frequency (20 kHz gives 40 kHz); 128 kbps MP3 for 180 seconds is only 2.75 MiB Explain lossy versus lossless
42-56 min 12-question diagnostic Four question types, marked on the spot: 9 right, 3 wrong Independent work
56-60 min Exit check Three oral questions; any miss points to the stage to reteach Oral answers

03 Teaching script (read it out)

Scene 1: Units are the foundation

One Byte is eight bits, and every step up multiplies by 1024 (KiB, MiB, GiB). Many students mix MB and MiB; exam questions usually mean 1024, but follow the paper when it states 1000.
Teaching move: require every answer to begin with one written line stating whether the given value is in bit or Byte, which protects the whole calculation.

Students do: express 6,220,800 Byte in both MiB and MB and explain the difference.

Scene 2: Two formulas, one skeleton

Images: width times height times colour depth divided by eight gives 6,220,800 Byte, which is 5.93 MiB after two divisions by 1024. Audio: sampling rate times bit depth divided by eight, times channels, times seconds gives 31,752,000 Byte, or 30.28 MiB.
Both are the same skeleton: data per unit times the number of units, divided by eight to turn bit into Byte. Name the skeleton and nothing needs memorising separately.

Students explain: compute a 1280 by 720 image at 24-bit (answer 2,764,800 Byte, about 2.64 MiB).

Scene 3: Compression: three trade-offs

Lossy compression discards detail the eye or ear barely notices. The 180-second stereo original is 30.28 MiB while a 128 kbps MP3 is 2.75 MiB, about 9 percent of the original, saving 91 percent. Lossless formats such as FLAC and PNG restore exactly but typically only halve the size. Sampling theorem: to keep 20 kHz you need at least 40 kHz, and 8-bit colour gives 256 levels.

Students do: compress the same clip at 64 kbps and 256 kbps, and say which file is larger and why.

04 Question types and worked steps

Type Example Steps Answer
Image size 1920 by 1080 at 24-bit Width times height times depth divided by 8 6,220,800 Byte (5.93 MiB)
Audio size 44.1 kHz, 16-bit, stereo, 180 seconds Rate times depth divided by 8, times channels and seconds 31,752,000 Byte (30.28 MiB)
Compression ratio Original 30.28 MiB, MP3 2.75 MiB Compressed over original times 100 9 percent (saves 91 percent)
Sampling rate Top frequency 20 kHz Nyquist: multiply by 2 40 kHz
Sanity check (teach this): Sanity checks: compressed size must be smaller than the original; sampling rate must exceed twice the top frequency; doubling colour depth doubles the file; doubling each side quadruples the area; 9 of 12 is 75 percent, not 9 percent.

05 Independent practice (3 questions)

Question Answer What to watch
Two image items 800 by 600 at 8-bit; 1920 by 1080 at 24-bit Did they divide by eight
Two audio items 44.1 kHz mono for 60 seconds; 22.05 kHz stereo for 120 seconds Did they multiply channels and seconds
Three mixed items Compression ratio, Nyquist, how many photos fit in 4 GB Are units consistent

06 Common mistakes and what to say

Mistake Student writes Say this
kHz read as Hz Substituting 44.1 for 44.1 kHz 44.1 kHz is 44100 Hz, and the formula needs Hz.
bit read as Byte Treating 24-bit depth as 24 Byte per pixel The 24 refers to bits; after dividing by eight a pixel is three Byte.
Channels ignored Computing stereo as mono Stereo carries two channels, so double the data before dividing by eight.
Lossy called lossless Claiming MP3 restores perfectly MP3 is lossy and cannot restore discarded detail; use FLAC or WAV for exact restoration.

07 Homework (paper, section and question numbers)

08 Exit check (last 5 minutes)

Question Answer Decision
Bytes for 1920 by 1080 at 24-bit 6,220,800 Missing the divide by eight means reteach stage two
Which Hz value for 44.1 kHz 44100 Answering 44.1 means reteach stage one
Is MP3 lossy or lossless Lossy, cannot restore exactly Answering lossless means reteach stage three

09 Tutor FAQ

Should we use 1000 or 1024?

Follow the paper when it states one; otherwise storage conventionally uses 1024 and network bandwidth uses 1000, and one sentence stating the assumption is enough.

How much encoding must be memorised?

ASCII in 7 bits and commonly 8, plus variable-length Unicode (1 Byte for English, usually 3 Byte for Chinese) is sufficient.

Why study Nyquist?

It explains why CDs use 44.1 kHz: hearing tops out near 20 kHz, and sampling must exceed twice that to avoid distortion.

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