S4 Physics: Electricity and Magnetism Practice Paper 4
- 2026-11-01
S4 Physics: Electricity and Magnetism Practice Paper 4
Paper four drills charge, Ohm law, three in series and V^2 over R, then a 20 and 5 ohm pair, parallel current sharing and a monthly bill, before a mixed network and an 80% efficient kettle, ending with the power versus resistance mix-up.
Quick answer 10 C, 20 V, 12 ohms, 24 W, 4 ohms, 6 A and 4 A, 180 kWh and $198, 3 A and 1 A, 210 s, 4 ohms.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | 25 minutes |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: S4 Physics: Electricity and Magnetism – Tutor Lesson Plan |
| Level | S4 |
02 Questions (10 items)
- FoundationA circuit carries 0.4 A for 25 s. Find the charge that passes.
- FoundationA current of 2.5 A flows through an 8 ohm resistor. Find the voltage across it.
- FoundationThree 4 ohm resistors are in series. Find the total resistance.
- FoundationA 6 ohm resistor is connected to a 12 V supply. Find its power.
- IntermediateA 20 ohm and a 5 ohm resistor are in parallel. Find the equivalent resistance.
- IntermediateA 6 ohm and a 3 ohm resistor are in parallel across 12 V. Find the total current and the current in the 3 ohm.
- IntermediateAn appliance rated 2 000 W runs 3 h a day for 30 days at $1.1 per kWh. Find the energy used and the cost.
- ChallengeA 4 ohm resistor is in series with a parallel pair of 6 ohms and 3 ohms across 18 V. Find the total current and the current in the 6 ohm.
- ChallengeA 3 000 W kettle of 80% efficiency heats 1.5 kg of water from 20 C to 100 C. Find the time needed. (c = 4 200 J/(kg K))
- Error redoA resistor takes 3 A from a 12 V supply. Find its resistance. A common mistake gives 36 ohms; why is that wrong?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | 10 C (Q = I t = 0.4 x 25) | Current is charge per second, so multiply by the time. |
| 2 | 20 V (V = I R = 2.5 x 8) | Ohm law gives voltage as current times resistance. |
| 3 | 12 ohms (4 x 3) | A series circuit has one path, so resistances simply add. |
| 4 | 24 W (P = V^2 / R = 144 / 6) | With voltage and resistance, use V^2 / R for power. |
| 5 | 4 ohms (1/20 + 1/5 = 1/4) | Parallel branches add as reciprocals, so the result is below the smallest branch. |
| 6 | Equivalent 2 ohms, total 6 A, and 4 A through the 3 ohm | Branches share the same voltage, so current splits in inverse ratio to resistance. |
| 7 | 180 kWh, so $198 | Get kWh from kW and hours, then multiply by the days and the tariff. |
| 8 | Equivalent 6 ohms, total 3 A, 6 V across the pair, so 1 A through the 6 ohm | Combine the parallel pair first, then share voltage and current layer by layer. |
| 9 | 504 000 J useful, 630 000 J supplied, so 210 s | Get the useful energy, divide by efficiency, then by the power. |
| 10 | 4 ohms (12 / 3); 36 is the 36 W power from voltage times current | Resistance needs division; multiplying gives power instead. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
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