S5 Maths: Vectors – Dot Product, Parallel and Perpendicular (Paper 2: Intermediate)
Apply the dot product to parallel, perpendicular and section problems, working backwards from conditions, ten items with answers.
| Item | Detail |
|---|---|
| Questions | 10 |
| Suggested time | 20 |
| Difficulty mix | Foundation 3 · Intermediate 3 · Challenge 3 · Error redo 1 |
| Chapter | Chapter: S5 Maths: Vectors |
| Level | Intermediate |
| # | Answer | One-line note |
|---|---|---|
| 1 | 1 | Multiply matching components and add: 6 minus 5 is 1. |
| 2 | (0.6, 0.8) | Take the length 5 and divide each component by it. |
| 3 | k = -8 | Parallel means proportional components, so 2 times 4 equals negative 1 times k. |
| 4 | k = -6 | Perpendicular means a zero dot product, so k plus 6 is zero. |
| 5 | 13 | 25 plus 144 is 169, and its square root is 13. |
| 6 | (4, 4) | A midpoint averages the coordinates: 2 and 6 give 4, 1 and 7 give 4. |
| 7 | (2, 3) | P covers one quarter of AB, so 8 over 4 is 2 and 12 over 4 is 3. |
| 8 | 60 degrees | The dot product is 1 while the lengths are 1 and 2, so the cosine is 0.5 and the angle is 60 degrees. |
| 9 | About 4.12 (root 17) | 2a is (2, 4) and subtracting b gives (-1, 4), whose length is root 17, about 4.12. |
| 10 | Not necessarily; the vectors may simply be perpendicular | The zero vector gives a zero product, but perpendicular non-zero vectors also do. |
With an unknown, write the dot product or ratio equation before solving.Tutor Registration →
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