S6 Biology: Biotechnology Paper 1 (PCR, vectors and GM crops)
- 2026-11-03
S6 Biology: Biotechnology Paper 1 (PCR, vectors and GM crops)
Biotechnology rests on copying, cutting, inserting and screening DNA; number items need only doubling and ratio reasoning.
Quick answer 1,048,576 times; C is 20%; 4,096 bp; 5,200 bp; 800 bp; 25%; twofold; about 0.0029 expected hits; 400 mL; 2 to the power 30 is about 1.07 billion.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | 25 minutes |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: S6 Biology: Biotechnology |
| Level | S6 |
02 Questions (10 items)
- FoundationPCR doubles the DNA amount every cycle. After 20 cycles, how many times the original amount is present?
- FoundationIn a double-stranded DNA molecule adenine is 30% of all bases. What percentage is cytosine?
- FoundationEcoRI recognises a six base pair sequence. With four bases equally likely, how many bp apart is a site on average?
- FoundationA plasmid of 4,000 bp takes a 1,200 bp insert. How long is the recombinant plasmid?
- IntermediateA pre-mRNA is 1,100 bp long and carries two introns totalling 300 bp. How long is the mature mRNA after splicing?
- IntermediateA GM maize raises yield from 8 tonnes to 10 tonnes per hectare. What is the percentage increase?
- IntermediateIn gel electrophoresis a 500 bp fragment moves 6 cm while a 1,000 bp fragment moves 3 cm. How many times further does the short fragment travel?
- ChallengeA guide RNA is 20 nt long and the human genome is about 3.2 x 10^9 bp. How many random matches are expected, and is that specific enough?
- ChallengeA viral vector contains 5 x 10^8 particles per millilitre and a treatment needs 2 x 10^11 particles. How many millilitres are required?
- Error redoError repair: a student claims 30 PCR cycles give 30 times the original DNA. What is the correct figure?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | 1,048,576 times | Twenty doublings mean 2 to the power 20, which equals 1,048,576. |
| 2 | 20% | A and T take 60% together, so G and C share the remaining 40% and C is 20%. |
| 3 | every 4,096 bp | Each position has four possibilities, so six positions give 4 to the power 6, which is 4,096. |
| 4 | 5,200 bp | The vector length plus the insert gives 4,000 plus 1,200, which is 5,200 bp. |
| 5 | 800 bp | Splicing removes the introns, so 1,100 minus 300 leaves 800 bp. |
| 6 | 25% | The gain of 2 tonnes divided by the original 8 tonnes, times 100, gives 25%. |
| 7 | twice as far | Six divided by three is 2, because shorter fragments travel faster through the gel. |
| 8 | about 0.0029 expected matches, under one, so usually a single target site | Four to the power 20 is about 1.1 x 10^12, and 3.2 x 10^9 divided by it gives 0.0029, so the site is nearly unique. |
| 9 | 400 mL | Two times 10 to the 11 divided by five times 10 to the 8 gives 400. |
| 10 | about 1.07 billion times (2^30 = 1,073,741,824) | PCR doubles every round, so growth is exponential rather than additive; 30 rounds give 2 to the power 30. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
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