S6 Biology: Biotechnology Paper 4 (combined calculations and error spotting)
- 2026-11-03
S6 Biology: Biotechnology Paper 4 (combined calculations and error spotting)
Paper 4 chains length, base ratios, fold increase and recovery yield: list what is known, decide whether to multiply or divide, then check that the units and order of magnitude make sense.
Quick answer 4,800 bp; T is 22%; 40 copies; ten sites; about 5.24 x 10^7 copies; eight times; 20%; about 0.0027 matches; 30 g; 24 g recovered; about 1.07 x 10^9 fold.
01 Paper details (check answers afterwards)
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | 25 minutes |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: S6 Biology: Biotechnology |
| Level | S6 |
02 Questions (10 items)
- FoundationA 3,500 bp plasmid takes a 1,300 bp insert. What is the recombinant length?
- FoundationIn a double-stranded DNA guanine is 28% of the bases. What percentage is thymine?
- FoundationStarting from five copies, three PCR cycles run. How many copies result?
- FoundationAn enzyme recognises four base pairs. How many sites does a 2,560 bp plasmid have on average?
- IntermediateFifty copies run through twenty cycles. How many copies are expected?
- IntermediateIn a gel a 4,000 bp fragment moves 1.2 cm and a 500 bp fragment moves 9.6 cm. How many times further does the short one travel?
- IntermediateA 4.8 kb vector takes a 1.2 kb insert. What percentage of the recombinant plasmid is the insert?
- ChallengeA guide RNA is 20 nt and the genome is about 3.0 x 10^9 bp. How many random matches are expected?
- ChallengeA plant runs three 400 L batches at 25 mg per litre with eighty per cent recovery. What are the theoretical and actual masses in grams?
- Error redoError repair: a student says thirty PCR cycles make thirty times the DNA. What is correct?
03 Answers and one-line notes
| # | Answer | One-line note |
|---|---|---|
| 1 | 4,800 bp | Three thousand five hundred plus one thousand three hundred is 4,800 bp, the sum of both segments. |
| 2 | 22% | G and C take 56% together, so A and T share the remaining 44% and T is 22%. |
| 3 | 40 copies | Three cycles multiply by eight, and five times eight is 40 copies. |
| 4 | ten sites | A four-base cutter averages one site every 256 bp, and 2,560 divided by 256 is ten. |
| 5 | about 5.24 x 10^7 copies | Two to the power 20 is 1,048,576, and times fifty gives about 5.24 x 10^7 copies. |
| 6 | eight times as far | Nine point six divided by 1.2 is 8, and shorter fragments travel further within the same gel. |
| 7 | 20% | The total is 6.0 kb, and 1.2 divided by 6.0 times one hundred is 20%. |
| 8 | about 0.0027 matches | Four to the power 20 is about 1.10 x 10^12, and 3.0 x 10^9 divided by it is about 0.0027, fewer than one. |
| 9 | 30 g theoretically, 24 g recovered | Three times 400 is 1,200 L, times 25 mg gives 30,000 mg that is 30 g, and times 0.8 gives 24 g. |
| 10 | about 1.07 x 10^9 fold, doubling every cycle | Each cycle multiplies by two rather than adding one, so thirty cycles give two to the power 30, about 1.07 x 10^9 fold. |
04 What to do after marking
- After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
- Repeat the same item two days later; move to the next paper only when both attempts are correct.
- Parents only need the answer and note columns; there is no need to explain every item.
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