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A-Level Chemistry Past Papers & Drilling (Paper 5): Titration Planning, Error Analysis
TUTORZONE ORIGINAL DRILLING MOCK · CAMBRIDGE A-LEVEL CHEMISTRY (9701) PAPER 5
Written to the Cambridge 9701 syllabus: Paper 5 Planning, Analysis and Evaluation, 30 marks, 1 h 15 min (experimental skills, AO3); plus Paper 1 MCQ (40), Paper 2 AS structured (60) and Paper 4 A Level structured (100). This is a Paper 5 drilling mock: 3 questions for 45 marks of practice, with answers and techniques.
What is in A-Level Chemistry (9701) Paper 5?
Direct answer: Paper 5 Planning, Analysis and Evaluation, 30 marks, 1 h 15 min (experimental skills, AO3).
Assessment at a glance (2027)
| Component | Content | Weighting | Duration |
|---|---|---|---|
| Paper 5 (Planning, Analysis and Evaluation) | Planning + analysis, 30 marks | A Level 12% | 1 h 15 min |
| Paper 4 (A Level Structured Questions) | Structured questions, 100 marks | A Level 38.5% | 2 hours |
A-Level Chemistry Paper 5 drilling technique: plans need apparatus (with range and precision), method, safety and repeats; concentration uses c1v1 = c2v2 (1:1 ratio); evaluation covers random (repeats) and systematic (instrument, end point) error. Percentage uncertainty = error / reading x 100%.
How this paper was built
This is a TutorZone original drilling mock: the questions follow the Cambridge 9701 structure (Paper 5, 30 marks) and the answers are our own, not Cambridge past papers or marking references.
Every numeric answer was recomputed programmatically.
Pacing
| Section | Marks | Suggested time | What to do first |
|---|---|---|---|
| Paper 5 (Planning, Analysis and Evaluation) | A Level 12% | about 37 min per question | apparatus choice + error reasoning |
| Paper 4 (A Level Structured Questions) | A Level 38.5% | about 12 min per question | AS + A2 content |
How is titration concentration found?
Direct answer: c1v1 = c2v2 (1:1 ratio); 0.100 x 20.0 / 25.0 = 0.080 mol/dm3.
Paper 5: planning and evaluation drilling (3 demonstrated)
State apparatus range and precision; c1v1 = c2v2.
Question 1 (15 marks)
Plan a titration: 0.100 mol/dm3 NaOH against 25.0 cm3 of HCl of unknown concentration; state the apparatus.
Question 2 (15 marks)
20.0 cm3 of 0.100 mol/dm3 NaOH reacts with 25.0 cm3 of HCl. Find the HCl concentration and assess the errors.
Question 3 (15 marks)
A pipette delivers 25.0 cm3 with precision ±0.05 cm3. Find the percentage uncertainty and how to reduce it.
How is percentage uncertainty found?
Direct answer: error / reading x 100%; 25.0 cm3 ± 0.05 cm3 gives 0.2%.
Paper 5 answers
Question 1
(1) Pipette 25.0 cm3 of HCl into a conical flask and add phenolphthalein (5). (2) Add NaOH from a burette dropwise to the end point (5). (3) Repeat three times, average, and record initial and final readings (5).
Question 2
1:1 ratio: c(HCl) = 0.100 x 20.0 / 25.0 = 0.080 mol/dm3 (7). Error sources: burette reading (±0.05 cm3), end-point judgement, air bubbles (8).
Question 3
Percentage uncertainty = 0.05 / 25.0 x 100% = 0.2% (7). Reduce it by using a more precise instrument, repeating and averaging, and reading consistently (bottom of the meniscus) (8).
Which topics does this paper drill?
Direct answer: titration planning, apparatus choice, concentration calculation, uncertainty and error sources.
Where these marks are usually lost
| Mistake | What it looks like | What it costs | Instead |
|---|---|---|---|
| Titration ratio wrong | Taken as 1:2 | NaOH:HCl is 1:1 | 0.080 mol/dm3 |
| Uncertainty denominator | Divide by the error | Divide by the reading | 0.2% |
| Readings not recorded | Final value only | Record initial and final readings | both readings |
How to use this paper
First drill: the full 1 h 15 min on all questions with no references.
Mark it: check the apparatus specifications and the concentration calculation.
Second drill: redo three to seven days later, aiming to finish inside 1 hour.
What should I do after drilling this paper?
Direct answer: log answers with a wrong mole ratio or missing readings; redo in three to seven days; and drill Paper 4 structured questions.
FAQ
Is this a Cambridge past paper?
No. The questions and answers are TutorZone originals, not Cambridge past papers or marking references.
What is in A-Level Chemistry 9701 Paper 5?
Planning, analysis and evaluation, 30 marks, 1 h 15 min, experimental skills (AO3).
How is titration concentration found?
c1v1 = c2v2 (1:1 mole ratio).
Official references
| Resource | What to check |
|---|---|
| Cambridge A-Level Chemistry 9701 page | Confirm the Paper 1-5 marks and times |
| https://www.tutorzone.com.hk/en-alevel-chemistry-9701-paper-1-mock-2027/ | A-Level Chemistry Paper 1 drilling mock |
Related: practice area · A-Level Chemistry Paper 2 drilling mock
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