HKDSE Visual Arts Practice Paper: Visual Elements, Art Criticism and Creative Practice (12 Questions, 100 Marks, 75 Minutes, with Answers)
- 2026-11-04
HKDSE Visual Arts: visual elements, art criticism and creative practice in one full mock paper
HKDSE Visual Arts paper: visual elements, rule of thirds, colour mixing, hue, perspective, print dpi, exposure, human proportion, art criticism, symbols and hanging calculations.
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Paper details Level: S6 | Subject: Visual Arts | Time: 75 minutes | Marks: 100 | Questions: 12 | Answers included
Section A: Visual Elements and Formal Analysis (32 marks)
Answer ALL questions.
| # | Question | Answer and marking notes |
|---|---|---|
| 1 | A 60 cm × 90 cm canvas is divided by the rule of thirds with two vertical and two horizontal lines. (a) Find the distance of each line from the nearest edge. (4 marks) (b) Find the length, width and area of the centre cell, and give its area as a percentage of the canvas. (4 marks) |
(a) Vertical lines are 20.0 cm and 40.0 cm from the left and right edges; horizontal lines are 30.0 cm and 60.0 cm from the top and bottom edges. (b) Centre cell 20.0 cm x 30.0 cm = 600 cm2; canvas 60 x 90 = 5,400 cm2; 600 / 5,400 x 100% = 11.11%. Marking: four distances 2 marks; length and width 2 marks; area 2 marks; percentage 2 marks. |
| 2 | Colour A is RGB(200, 60, 40) and colour B is RGB(40, 80, 200). (a) Find the RGB value when the two colours are mixed 1:1. (4 marks) (b) Give the complementary RGB of colour A and explain why placing complementary colours side by side strengthens contrast. (4 marks) |
(a) (200+40)/2=120, (60+80)/2=70, (40+200)/2=120, so the mixture is RGB(120, 70, 120). (b) Complementary = 255 minus each channel, i.e. RGB(55, 195, 215). The two hues sit 180 degrees apart on the wheel, so each makes the other look more vivid and contrast is strengthened. Marking: three channels 1 mark each (3); complementary value 2; contrast explanation 3. |
| 3 | A canvas 100 cm wide is divided by the golden ratio (about 1:1.618) into a long and a short section. (a) Find the length of each section in cm, to 1 decimal place. (4 marks) (b) Compare the division points of the golden ratio and the rule of thirds, and state their shared visual aim. (4 marks) |
(a) Long section = 100 x 1.618 / 2.618 = 61.8 cm; short section = 100 – 61.8 = 38.2 cm. (b) The golden section falls near 61.8% and 38.2%, the rule of thirds at 33.3% and 66.7%. Both move the subject off centre, avoiding static symmetry while keeping balance and creating movement. Marking: long 2, short 2; comparison of positions 2; shared aim 2. |
| 4 | A lens of focal length 50 mm photographs a 1.8 m tall work; the sensor is 24 mm high. Image height = focal length x object height / distance. (a) Find the image height at 10 m and at 20 m, in mm. (4 marks) (b) Explain how image height changes when distance doubles, and what this means for recorded detail. (4 marks) |
(a) At 10 m: 50 x 1800 / 10,000 = 9.0 mm; at 20 m: 50 x 1800 / 20,000 = 4.5 mm. (b) Doubling the distance halves the image height, because image height is inversely proportional to distance. A smaller image records less detail, so the photographer must move closer or use a longer lens. Marking: each image height 2 marks; inverse relation 2; detail effect 2. |
Section B: Media, Technique and Data (36 marks)
Show all working and give units in calculation questions.
| # | Question | Answer and marking notes |
|---|---|---|
| 5 | An A4 work (210 mm x 297 mm) is scanned at 300 dpi. Pixels = size in mm / 25.4 x dpi. (a) Find the pixel dimensions, rounded to whole numbers. (5 marks) (b) What happens to the pixel dimensions at 150 dpi, and how does this affect print quality? (4 marks) |
(a) 210 / 25.4 x 300 = 2,480 px; 297 / 25.4 x 300 = 3,508 px, about 2,480 x 3,508 pixels. (b) At 150 dpi the size is about 1,240 x 1,754 pixels: each side halves and total pixels fall to one quarter, so enlargement shows jagged edges and lost detail. Marking: two pixel values 2 marks each (4); 150 dpi figures 2; quality explanation 3. |
| 6 | A photographer uses aperture f/4 and shutter 1/250 s for correct exposure. Standard aperture stops are f/2, f/2.8, f/4, f/5.6, f/8; shutter stops are 1/500, 1/250, 1/125, 1/60, 1/30 s. (a) If the aperture is closed to f/5.6, how should the shutter change to keep the exposure constant? (5 marks) (b) Explain the light change per aperture stop and its effect on depth of field. (4 marks) |
(a) f/4 to f/5.6 is one stop closed, halving the light, so the shutter must slow one stop from 1/250 s to 1/125 s. (b) Each stop open doubles the light (aperture value divided by root two). A wider aperture gives shallower depth of field and a softer background; a smaller aperture deepens it but needs a slower shutter or higher sensitivity. Marking: shutter 3, direction 2; light relation 2; depth of field 2. |
| 7 | On a twelve-hue wheel red is at 0 degrees, yellow at 60 and blue at 240. (a) Find the analogous hues of red (plus or minus 30 degrees), its complementary hue (+180 degrees) and its triadic hues. (5 marks) (b) Explain how warm and cool hues affect the sense of space in a picture. (4 marks) |
(a) Analogous hues are 330 degrees (red violet) and 30 degrees (red orange); the complement is 180 degrees (cyan green); triadic hues are 120 degrees (green) and 240 degrees (blue). (b) Warm hues (red, orange, yellow) advance and seem closer; cool hues (blue, green, violet) recede and seem distant, so they are often used in backgrounds to build depth. Marking: analogous 2, complementary 1, triadic 2; warm 2, cool 2. |
| 8 | A life drawing uses the 7.5-head proportion. (a) For a model 168 cm tall, what is the head height? (5 marks) (b) What is the head height at 8 heads, and what visual effect does the change create? (4 marks) |
(a) 168 / 7.5 = 22.4 cm. (b) 168 / 8 = 21.0 cm. The head becomes smaller relative to the body and the legs longer, giving a slim, idealised figure often used in fashion illustration. Marking: working 2, answer 3; 8-head answer 2; effect 2. |
Section C: Criticism, Context and Creation (32 marks)
Support criticism and design answers with specific visual evidence.
| # | Question | Answer and marking notes |
|---|---|---|
| 9 | Art criticism usually follows description, analysis, interpretation and judgement. Consider a thickly painted harbour night scene. (a) For the analysis step, give two observable formal elements and their effects. (4 marks) (b) Explain why judgement must rest on the first three steps. (4 marks) |
(a) Example one: thick paint builds repeated highlights, giving a flickering texture; example two: deep blue against orange light exploits complementary contrast and dark surroundings focus attention. (b) Judgement needs accurate description, formal analysis and contextual interpretation as evidence, so that the verdict is grounded rather than a matter of personal taste. Marking: each observation with effect 2 marks (4); evidence and judgement 4. |
| 10 | The meaning of visual symbols often depends on cultural context. Consider a dove, a crack and a red door. (a) Give one common symbolic meaning for each. (3 marks) (b) Give one example of the same symbol read differently in two cultures, and say how a maker should handle this. (5 marks) |
(a) Dove: peace; crack: rupture or crisis; red door: opportunity or taboo (1 mark each, any sound answer). (b) Example: white signals purity in some cultures but mourning in others. A maker should study the exhibition setting and audience, and use titles, text or juxtaposition to steer reading. Marking: three symbols 1 mark each; example 3; handling 2. |
| 11 | The three distances of Chinese landscape painting and Western one-point perspective are two ways of building space. (a) Describe the viewing method of high distance, deep distance and level distance. (3 marks) (b) Compare the two systems in terms of viewer position and spatial construction. (5 marks) |
(a) High distance looks up at the peak; deep distance peers from front to back in layered depth; level distance looks from near to far across an open plain. (b) The three distances use a moving viewpoint, so several views coexist and space unfolds as the eye travels; one-point perspective fixes a single viewpoint and vanishing point, unifying space by mathematical proportion into an illusion of depth. Marking: three distances 1 mark each; viewpoint 3; spatial construction 2. |
| 12 | Three works 80 cm, 60 cm and 100 cm wide hang on a 600 cm wall, with 70 cm left at each end and equal gaps between works. (a) Find the gap between works. (5 marks) (b) State the height for the centre of the works and explain why. (3 marks) |
(a) Wall 600 cm – margins 140 cm – works 240 cm = 220 cm; 220 / 2 = 110 cm. (b) Centres are usually hung at eye level, about 145 to 150 cm, so viewers look naturally without straining the neck. Marking: margins 2, work widths 2, division 1; height 2; reason 1. |
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