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IGCSE Chemistry Past Papers & Drilling (Paper 3): Ions, Neutralisation, Redox

IGCSE Chemistry Past Papers & Drilling (Paper 3): Ions, Neutralisation, Redox

  • 2026-10-13

TUTORZONE ORIGINAL DRILLING MOCK · CAMBRIDGE IGCSE CHEMISTRY (0620) PAPER 3

Written to the Cambridge 0620 syllabus: Paper 3 Theory (Core), 80 marks, 1 h 15 min, 50% (short-answer and structured); plus Paper 1 Multiple Choice (Core, 40 marks, 30%). This is a Paper 3 drilling mock: 6 questions for 80 marks with answers and techniques.

What is in IGCSE Chemistry (0620) Paper 3?

Direct answer: Paper 3 Theory (Core), 80 marks, 1 h 15 min, 50% (short-answer and structured).

Hong Kong student drilling IGCSE Chemistry Paper 3 with reaction equations and apparatus
Paper 3 theory (Core): 80 marks, 1 h 15 min, 50% – drilling.

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01

Assessment at a glance (2027)

Component Content Weighting Duration
Paper 3 (Theory, Core) Short-answer and structured, 80 marks 50% 1 h 15 min
Paper 1 (Multiple Choice, Core) 40 four-option items, 40 marks 30% 45 min

IGCSE Chemistry Paper 3 drilling technique: balance equations; ion electrons = protons ± charge; oxidation is loss, reduction is gain (OIL RIG); ionic compounds melt high because ionic bonds are strong.

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How this paper was built

This is a TutorZone original drilling mock: the questions follow the Cambridge 0620 structure (Paper 3 Core, 80 marks, 50%) and the answers are our own, not Cambridge past papers or marking references.

Every numeric answer was recomputed programmatically.

Note before you start: this is not a Cambridge past paper. Your score is a practice score and cannot be converted into an IGCSE grade.
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Pacing

Section Marks Suggested time What to do first
Paper 3 (Theory, Core) 50% about 9 min per question equations + explanation
Paper 1 (Multiple Choice, Core) 30% about 68 s per question core content only

How are oxidation and reduction defined by electrons?

Direct answer: oxidation is loss of electrons, reduction is gain (OIL RIG).

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Paper 3: core theory drilling (6 questions, 80 marks)

Balance equations; remember OIL RIG for redox.

Question 1 (14 marks)

How many electrons are in Na+ and Cl-? Explain why Na+ is positive.

Question 2 (13 marks)

Calculate the Mr of H2O (H = 1, O = 16) and explain why ionic compounds have high melting points.

Question 3 (13 marks)

Write the neutralisation equation for hydrochloric acid and sodium hydroxide and state the pH of the product.

Question 4 (13 marks)

Define oxidation and reduction in terms of electron transfer.

Question 5 (13 marks)

Explain why aluminium is unreactive in practice despite being reactive.

Question 6 (14 marks)

State two differences between alkanes and alkenes in structure and reactions.

How many electrons are in Na+?

Direct answer: 10 (it loses one electron, so protons outnumber electrons).

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Paper 3 answers

Question 1

Na+ has 10 electrons and Cl- has 18 (7); Na+ lost one electron so protons outnumber electrons, giving a positive charge (7).

Question 2

Mr = 2×1 + 16 = 18 (7); ionic compounds are held by strong electrostatic attraction (ionic bonds) needing much energy to break (6).

Question 3

HCl + NaOH -> NaCl + H2O (7); the product is a neutral salt solution, pH about 7 (6).

Question 4

Oxidation is loss of electrons (7); reduction is gain of electrons (6).

Question 5

Aluminium forms a thin, tough layer of aluminium oxide (7) that prevents further oxidation (protective layer) (6).

Question 6

Structure: alkanes have only single bonds (saturated) and alkenes have a C=C double bond (unsaturated) (7). Reactions: alkenes undergo addition (decolourising bromine water) while alkanes mainly burn (substitution) (7).

Which topics does this paper drill?

Direct answer: ion electron counts, ionic bonding and melting points, neutralisation, redox, protective layers, alkanes and alkenes.

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Where these marks are usually lost

Mistake What it looks like What it costs Instead
Ion electron count Na+ with 11 electrons Na+ has 10 after losing one 10
Unbalanced equation Miss coefficients Check atoms on both sides balanced
Redox reversed Oxidation = gain Oxidation = loss (OIL RIG) loss
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How to use this paper

First drill: the full 1 h 15 min on all 6 questions with no references.

Mark it: check equation balancing and electron counts.

Second drill: redo three to seven days later, aiming to finish inside 1 hour.

What should I do after drilling this paper?

Direct answer: log unbalanced equations or wrong electron counts; redo in three to seven days; and drill Paper 4 (Extended theory).

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FAQ

Is this a Cambridge past paper?
No. The questions and answers are TutorZone originals, not Cambridge past papers or marking references.

What is in IGCSE Chemistry Paper 3?
Theory (Core), 80 marks, 1 h 15 min, 50%, short-answer and structured questions.

How are oxidation and reduction defined by electrons?
Oxidation is loss of electrons; reduction is gain (OIL RIG).

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Official references

Resource What to check
Cambridge IGCSE Chemistry 0620 page Confirm the paper marks and times
https://www.tutorzone.com.hk/en-igcse-chemistry-0620-paper-1-mock-2027/ IGCSE Chemistry Paper 1 drilling mock

Related: practice area · IGCSE Chemistry Paper 2 drilling mock

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