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IGCSE Environmental Management Past Papers & Drilling (Paper 1): Energy, Soil, Water and Air

IGCSE Environmental Management Past Papers & Drilling (Paper 1): Energy, Soil, Water and Air

  • 2026-10-15

TUTORZONE ORIGINAL DRILLING MOCK · CAMBRIDGE IGCSE ENVIRONMENTAL MANAGEMENT (0680) PAPER 1 PRINCIPLES

Written to the 0680 syllabus (2027-2029): Paper 1 Principles of Environmental Management, 80 marks in 1 h 45 min, 50% of the qualification, a written paper with all questions compulsory and grades A* to G. This drilling paper covers natural resources, land and soil, water resources and pollution, and the atmosphere, with invented data, worked answers and technique.

What is in Cambridge IGCSE Environmental Management (0680)?

Direct answer: 0680 has two compulsory papers: Paper 1 Principles of Environmental Management and Paper 2 Environmental Management in Context, each 80 marks in 1 h 45 min and worth 50%; both are written papers with all questions compulsory and grades run A* to G. Paper 1 combines short-answer and structured questions with an extended response based on source material.

Renewable energy in the field: a solar array beside wind turbines on farmland
Paper 1 Principles of Environmental Management, 80 marks in 1 h 45 min: drilling resources, land, water and atmosphere.

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Assessment at a glance (2027)

Component Content Weighting Duration
Paper 1 (Principles of Environmental Management) 80 marks: short-answer and structured questions, plus one extended response that uses the source material; all questions compulsory 80 · 50% 1 h 45 min
Paper 2 (Environmental Management in Context) 80 marks: short-answer items, data processing and analysis, and an extended response that uses the source material; all questions compulsory 80 · 50% 1 h 45 min

Paper 1 technique: 80 marks in 1 h 45 min is about 1.3 minutes per mark. Show the formula and the unit in every calculation: years of reserves = reserves / annual extraction; net erosion = erosion minus soil formation; topsoil mass = depth x bulk density x 1000; water stress compares availability per person with 1700 m3; mixed BOD is weighted by flow; a percentage rise takes the original value as the denominator. For the extended response state a position, give two or three data-based points and finish by comparing the strategies.

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How this paper was built

This is a TutorZone original drilling mock: the questions follow the Cambridge 0680 Paper 1 structure (80 marks, 1 h 45 min, short-answer and structured questions with an extended response) and the answers are our own, not Cambridge past papers or marking references.

Every data set (energy mix, erosion rates, BOD, methane concentration) was invented for drilling and is not official statistics for any country; each numeric answer was recomputed programmatically.

Note before you start: this is not a Cambridge past paper. Your score is a practice score and cannot be converted into an IGCSE grade.
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Pacing

Section Marks Suggested time What to do first
Paper 1 (Principles of Environmental Management) 80 · 50% about 1.3 min per mark calculations first, extended response last
Paper 2 (Environmental Management in Context) 80 · 50% about 1.3 min per mark process the data table first, extended response last

How do you calculate soil erosion and topsoil loss?

Direct answer: net erosion = 12.0 – 0.8 = 11.2 tonnes per hectare per year; topsoil mass = 0.15 x 1.35 x 1000 = 202.5 kg per m2; annual loss = 12.0 / 10 = 1.2 kg per m2, so the topsoil would be gone in about 169 years.

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Paper 1: four structured and extended questions (4 questions, 80 marks)

Question 1 natural resources, question 2 land and soil, question 3 water resources and pollution and question 4 the atmosphere and human activities, 20 marks each; the official paper is organised differently and this mock distributes the marks evenly across four topics. Allow the full 1 h 45 min.

Question 1 (20 marks)

Question 1: Natural resources (20 marks)
Invented city energy data: coal 38%, gas 24%, nuclear 8% and renewables 30%; coal reserves are 4800 million tonnes with 160 million tonnes extracted each year.
(a) Calculate how many years the coal reserves would last at the present rate of extraction. (4 marks)
(b) Calculate the combined percentage of low-carbon energy (nuclear and renewables) in the energy mix. (4 marks)
(c) State two environmental problems that hydraulic fracturing for shale gas can cause. (6 marks)
(d) Evaluate two management strategies: removing fossil-fuel subsidies and enforcing a renewable energy quota. (6 marks)

Question 2 (20 marks)

Question 2: Land and soil (20 marks)
Invented farm data: soil erosion runs at 12.0 tonnes per hectare per year while soil forms at 0.8 tonnes per hectare per year; topsoil is 0.15 m deep with a bulk density of 1.35 tonnes per cubic metre; conventional yields are 6.8 tonnes per hectare and organic yields 5.2 tonnes per hectare.
(a) Calculate the net erosion rate and the cumulative loss over 20 years. (5 marks)
(b) Calculate how long the topsoil would take to be lost completely (1 tonne per hectare = 0.1 kg per square metre). (5 marks)
(c) Calculate the yield gap of organic farming as a percentage of conventional yields. (3 marks)
(d) Evaluate the effectiveness of contour ploughing and cover crops for soil conservation. (7 marks)

Question 3 (20 marks)

Question 3: Water resources and pollution (20 marks)
Invented data: available water is 3.2 km3 a year for 2.4 million people; sewage has a BOD of 320 mg per litre before treatment and treatment is 85% effective; treated effluent of 0.5 m3/s enters a river with a BOD of 2.0 mg per litre and a flow of 8.0 m3/s; about 8 million tonnes of plastic enter the ocean each year against annual production of about 400 million tonnes.
(a) Calculate the available water per person per year and compare it with the 1700 m3 water-stress threshold. (5 marks)
(b) Calculate the BOD of the discharged effluent and of the river after mixing. (6 marks)
(c) Calculate the percentage of annual plastic production that reaches the ocean. (3 marks)
(d) Evaluate tertiary sewage treatment and reducing plastic at source as management measures. (6 marks)

Question 4 (20 marks)

Question 4: The atmosphere and human activities (20 marks)
Invented data: atmospheric methane rose from 700 ppb to 1900 ppb; sulphur dioxide emissions of 12.0 million tonnes a year are cut by 40%; the polar ozone column fell from 300 DU to 220 DU; global mean temperature has risen 1.1 C and a further 0.4 C would reach the 1.5 C goal.
(a) Calculate the percentage rise in methane. (4 marks)
(b) Calculate sulphur dioxide emissions after the cut. (4 marks)
(c) Calculate the percentage depletion of the ozone column. (4 marks)
(d) Express the further 0.4 C rise as a percentage of the warming already recorded and evaluate one mitigation measure. (8 marks)

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Extension drills: quarry restoration and irrigation efficiency (2 questions, not part of the 80 marks)

Two extension items cover mineral resources and agricultural water use; allow 12 minutes.

Question 1 (5 marks)

Extension Question 1: extraction and restoration (5 marks, not part of the 80-mark paper)
A quarry extracts 2.4 million tonnes of rock a year and has restored 96 of its 320 hectares. Calculate the annual extraction in tonnes per hectare and the restoration progress as a percentage.

Question 2 (5 marks)

Extension Question 2: irrigation efficiency (5 marks, not part of the 80-mark paper)
A farm applies 4800 m3 of irrigation water per hectare while the crop needs 3360 m3 per hectare. Calculate the irrigation efficiency and state one way to improve it.

How are effluent BOD and water stress judged?

Direct answer: effluent BOD = 320 x (1 – 0.85) = 48.0 mg per litre; after mixing = (0.5 x 48.0 + 8.0 x 2.0) / 8.5 = about 4.7 mg per litre; availability per person = 3.2 x 10^9 / 2,400,000 = about 1333 m3, below the 1700 m3 threshold.

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Paper 1 model answers

Question 1

(a) Years of coal = 4800 / 160 = 30 years. (4 marks)

(b) Low-carbon share = 8% + 30% = 38%, still below the 62% from fossil fuels combined. (4 marks)

(c) Hydraulic fracturing needs large volumes of water and chemicals, so groundwater can be contaminated; flowback fluids and methane leakage add greenhouse gases; operations can also trigger minor earthquakes, use scarce water and damage surface habitats. (any two, 6 marks)

(d) Removing subsidies closes the cost gap between fossil fuels and renewables immediately, but can raise electricity prices and meet political resistance; a renewable quota guarantees capacity and demand within a set period but needs grid investment and back-up capacity. Used together they change both price signals and supply structure, whereas a single tool tends to shift emissions elsewhere. (6 marks)

Question 2

(a) Net erosion = 12.0 – 0.8 = 11.2 tonnes per hectare per year; over 20 years the loss is 11.2 x 20 = 224.0 tonnes per hectare. (5 marks)

(b) Topsoil mass = 0.15 x 1.35 x 1000 = 202.5 kg/m2; annual loss = 12.0 / 10 = 1.2 kg/m2, so complete loss would take 202.5 / 1.2 = about 169 years. (5 marks)

(c) Yield gap = (6.8 – 5.2) / 6.8 x 100 = about 23.5%. (3 marks)

(d) Contour ploughing cuts slope length and slows runoff, reducing sheet and rill erosion; cover crops protect the surface in fallow periods and raise organic matter and infiltration. Both are cheap and easy to spread, yet they give limited protection on steep slopes and in extreme storms, so they need terracing, grass strips and reduced tillage alongside them – and farmers may resist the extra labour and short-term yield loss. (7 marks)

Question 3

(a) Water per person = 3.2 x 10^9 / 2,400,000 = about 1333 m3 a year, below the 1700 m3 threshold, so the area is water stressed. (5 marks)

(b) Effluent BOD = 320 x (1 – 0.85) = 48.0 mg per litre; after mixing = (0.5 x 48.0 + 8.0 x 2.0) / (0.5 + 8.0) = about 4.7 mg per litre. (6 marks)

(c) Share = 8 / 400 x 100 = 2.0%. (3 marks)

(d) Tertiary treatment removes nitrogen, phosphorus and pathogens and can bring effluent up to reuse standards, but it is energy-intensive and costly, which low-income regions struggle to fund; cutting plastic at source (single-use bans, producer responsibility, deposit return) is more cost-effective and reduces both ocean plastic and microplastics, yet depends on enforcement and collection infrastructure. The two belong together: clean the end of the pipe while cutting what enters it. (6 marks)

Question 4

(a) Rise = (1900 – 700) / 700 x 100 = about 171.4%. (4 marks)

(b) Emissions after the cut = 12.0 x (1 – 0.40) = 7.2 million tonnes. (4 marks)

(c) Depletion = (300 – 220) / 300 x 100 = about 26.7%. (4 marks)

(d) 0.4 / 1.1 x 100 = about 36.4%. A mitigation example (cutting methane): repairing leaks in gas pipelines and wells, capturing landfill gas and changing rice paddy irrigation. Because methane has a much higher hundred-year warming potential than carbon dioxide, cutting it slows warming quickly, but leak rates need continuous monitoring and mandatory disclosure or the reduction stays on paper. (8 marks)

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Extension answers

Question 1

Annual extraction per hectare = 2,400,000 / 320 = 7500 tonnes per hectare per year; restoration progress = 96 / 320 x 100 = 30%. Restoration must be staged during extraction, otherwise bare slopes increase soil loss and dust pollution.

Question 2

Irrigation efficiency = 3360 / 4800 x 100 = 70%. Improvements include drip or micro-spray irrigation, soil-moisture sensors that water on demand, and irrigating early in the morning to cut evaporation losses.

How should the time be shared across the four questions?

Direct answer: 80 marks in 1 h 45 min is about 1.3 minutes per mark: roughly 24 minutes per question, leaving 8 minutes to check units and the evaluation sentence.

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Where these marks are usually lost

Mistake What it looks like What it costs Instead
Reserve life over total extraction Dividing by 4800 The denominator is the annual 160 30 years
Erosion taken as soil formation Reporting 0.8 tonnes per hectare Net loss is 12.0 – 0.8 11.2 tonnes per hectare per year
Missing the 1000 conversion 0.15 x 1.35 = 0.2025 kg 1 tonne per m3 is 1000 kg per m3 202.5 kg per m2
Mixed BOD as a simple average (48 + 2) / 2 Weight by flow instead about 4.7 mg per litre
Percentage rise over the new value Using 1900 as the denominator A percentage rise uses the original 700 171.4%
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How to use this paper

First drill: the four questions in 1 h 45 min, writing the formula before each calculation.

Mark it: check every unit conversion and percentage denominator, and complete the evaluation paragraph.

Second drill: redo three to seven days later, aiming to finish inside 90 minutes with all calculations correct.

What should I do after drilling this paper?

Direct answer: log the questions where a unit conversion or a percentage denominator went wrong, redo the paper in three to seven days, then drill Paper 2 for data processing and fieldwork method questions.

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FAQ

Is this a Cambridge past paper?
No. This is not a Cambridge past paper: the questions, data and answers are TutorZone originals, not marking references.

What is in Cambridge IGCSE Environmental Management 0680 Paper 1?
Paper 1 Principles of Environmental Management: short-answer and structured questions plus an extended response based on source material, 80 marks in 1 h 45 min and 50% of the qualification; there are two papers and grades run A* to G.

Do candidates take both papers?
Yes. All candidates take Papers 1 and 2, each worth 50%; the qualification is not tiered.

Can I just write the answer for a calculation?
No. Cambridge marking requires the method and the unit, so a bare number loses the method marks.

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Official references

Resource What to check
Cambridge IGCSE Environmental Management 0680 syllabus (2027-2029) Confirm the marks, time, topics and assessment objectives of both papers
Cambridge 0680 subject page with specimen papers Download the official specimen papers to check question styles and command words
https://www.tutorzone.com.hk/en-igcse-environmental-management-0680-paper-2-mock-2027/ IGCSE Environmental Management Paper 2 drilling mock

Related: practice area · Paper 2 in Context drilling mock · IGCSE Geography 0460 Paper 1 drilling mock

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