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IB Maths: Functions and Graphs – Practice Paper 3 (10 Questions)

IB Maths: Functions and Graphs – Practice Paper 3 (10 Questions)

  • 2026-10-30

IB Maths: Functions and Graphs – Practice Paper 3 (10 Questions)

Paper 3 concentrates on transformations and inverses: vertical shifts, reflections, vertical stretches, the order of composites, and the domains of inverse quadratic and root functions.

Quick answer Ten items, about twenty-five minutes. Items 01 to 04 cover substitution, domain and range and basic transformations; items 05 to 07 cover composite order, a cube-root inverse and a vertical stretch; items 08 and 09 are a completed square and a root inverse; item 10 redoes inverse notation.

01 Paper details (check answers afterwards)

Item Detail
Questions 10 questions
Suggested time 25 minutes
Difficulty mix Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1
Chapter Chapter: IB Maths: Functions and Graphs – Tutor Lesson Plan
Level IB SL

02 Questions (10 items)

  1. FoundationGiven f(x) = x squared minus three x, find f(4).
  2. FoundationState the domain and range of g(x) = 1 over x.
  3. FoundationThe graph of y = f(x) moves up by two units. What is the new equation?
  4. FoundationHow is the graph of y = -f(x) related to y = f(x)?
  5. Intermediatef(x) = 2x + 1 and g(x) = x – 3. Find f of g of x and its value at 4.
  6. Intermediatef(x) = x cubed. Find the inverse and the inverse at 27.
  7. IntermediateHow does the graph of y = 2f(x) differ from y = f(x)?
  8. ChallengeFor y = x squared minus four x plus seven, give the minimum and the range.
  9. Challengey = the square root of x plus 3 for x at least minus three. Find the inverse and its domain.
  10. Error redoA student treats the inverse at 2 as one over f of 2. With f(x) = 4x + 2, what is the inverse at 2?

03 Answers and one-line notes

# Answer One-line note
1 f(4) = 4 Sixteen minus twelve is four.
2 domain x not 0, range y not 0 The denominator cannot be zero and the fraction never reaches zero, so both sides exclude it.
3 y = f(x) + 2 A vertical shift is added to the whole value, while a change inside the bracket shifts sideways.
4 a reflection in the x axis Every y changes sign, so the curve flips over the x axis.
5 f(g(x)) = 2x – 5, and at 4 it is 3 Do g first, then f: two times x minus three plus one; at four the result is three.
6 inverse is the cube root, and at 27 it is 3 Cubing and taking a cube root undo each other, since three cubed is twenty-seven.
7 a vertical stretch by a factor of two Every y doubles, so the curve stretches vertically and its x-intercepts stay put.
8 minimum 3 at x = 2, range y at least 3 Completing the square gives a square plus three, so the least value is three.
9 inverse is x squared minus 3, domain x at least 0 Squaring both sides gives x equal to y squared minus three, and the old range x at least zero becomes the new domain.
10 the inverse at 2 is 0 The inverse is a function, not a reciprocal: solving four x plus two equals two gives zero, while the reciprocal would be one tenth.

04 What to do after marking

  • After marking, redo only the wrong items and write down which step went wrong (formula, unit, or misread number).
  • Repeat the same item two days later; move to the next paper only when both attempts are correct.
  • Parents only need the answer and note columns; there is no need to explain every item.

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