Primary 5 Maths: Triangle, Parallelogram and Trapezium Area — Practice Paper 3 (10 Questions)
Paper 3 is built around which line is the height: a slant side is not a height, and cutting a corner away means rectangle minus triangle. Item 09 takes the area all the way to a price.
| Item | Detail |
|---|---|
| Questions | 10 questions |
| Suggested time | 25 minutes |
| Difficulty mix | Foundation 4 · Intermediate 3 · Challenge 2 · Error redo 1 |
| Chapter | Chapter: Primary 5 Maths: Areas of Triangles, Parallelograms and Trapeziums |
| Level | Primary 5 |
| # | Answer | One-line note |
|---|---|---|
| 1 | 42 cm² | Base × height ÷ 2 = 12 × 7 ÷ 2. |
| 2 | 26.0 m² | No halving for a parallelogram: 6.5 × 4, keeping the decimal point. |
| 3 | 96 cm² | (9 + 15) × 8 ÷ 2; a trapezium needs ÷ 2 as well. |
| 4 | 16 cm | Reverse the formula: height = area × 2 ÷ base = 192 ÷ 12. |
| 5 | 6 m | No halving here, so simply 84 ÷ 14. |
| 6 | 204 cm² | Rectangle is 240 cm²; subtract the triangle 36 cm². |
| 7 | 12 m | Sum of the parallel sides = 72 × 2 ÷ 8 = 18, then subtract 6. |
| 8 | 50 trees | Area is 200 m², then divide by 4. |
| 9 | $21.6 | Area is 0.48 m², then × 45. |
| 10 | 84 cm² | The height must be perpendicular to the base, so not the slant side: 14 × 6. |
Questions and answers are written originally by the TutorZone team and are not taken from any school, publisher or examination authority paper. Every value is checked by computer.

